Sol-161E1-F2006 - 1 The graph Of 332" 633 8 — y = 0...

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Unformatted text preview: 1- The graph Of 332 " 633 + 8 — y = 0 is A. Moving it 4 units to the right and 3 units down obtained from the graph of y = 3:2 by B. Moving it 3 units to the left and 1 unit up 2 . : 96—32% . . . . . f x © Mov1ng 1t 3 units to the right and 1 unit down 13R , H) D. Moving it4units to the left and3units down E. Moving it 1 unit to the right and 3 units up 2. The solution to the inequality :1: g 53: — 3 < 8:1: — 2 is A. a: > _1 — 3 ’X S 59GB 993 _, \U/ 5. 3/304 2 $>§ 4 A. _ 4 3\ ’X. . I ’1 < 3% 1 3 3 \l/ - i < C’ _3 S a: < 1 f' €64 AND 3 IX 14 D —l < a: <§ 3 “ 4 3 E _ 32> 4 3 Given that sins: 2 and cosa:< 0 it follo sthat tan 'se alt 2 . : — , w 3:1 u o —— 5 q m I ‘ I ' 21 (1.6496 2 W :1 — 24 B. —% 5 C. —— . x/fi ‘51“ 0g :1 Hm“) : 4 D. —— Clo/>96 25 4 E. —— x/fi 4. The center C and radius r of the circle given by 129 x2+y2fllflx+3y25are A. C:(_§,5)7T:V2 V 129 2 2 _ _§ _ «6).. ”(a 2w— 5) /‘ , L 2 c. C:(5,—3), r27 C j : iii 30% :r7‘ 2 2 («~- 5. An equation of the line through (—2, 2) and parallel to 33/ + 41: + 2 : 0 4x + 33/ ~ 7 = 0 is C. -4x+3y—14:0 // W (~23) 12/ D. 4y+3$+2=0 E. 2x+3y—-2:0 “*2 = -i(%+a) #l/ .3 béf-M’x + 2 : O 6. Given that f(a:) = V4 —a:2 and 9(33) : V332 + 1, the A. [—f,—2] U [2,\/5] domain of g o f is B. [—x/5,\/5] 0’” ‘3) = (mam) o. W) Ola/”V (g) I {K i 44962303 2 E2) 2] D. (—00,—\/3]U[\/5,oo) m” M<3°é> 501%) = E23] CE) ”’21 7. Which of the following statements are true? Only I ‘T 1.5“3-53’ : 5““! F 11.(4-3)$:4z+3“‘ @001, 42%? F HI.8$+8y:8z+y é; Xga—J1J 46%;"4 C. Onlylandll D. Only III E. 1, H7 and Ill 8. The inverse of the function f(a:)= ::;: 131613“ )2 A' iii—2: 12.3 “a ___, __, 2$~5 jg}? ._.> 2x7+57.,33g»2 13-3433 C 2x+3 :5 (2x296: ~2—57C 5—206 ’ 5x+2 @ €3519C+2 3‘21: 3__ 2% 333—2 E. 3—53: 9. lim m_f_ _,ZM‘ {\l2;(+5~J-TT)\J27(+5 44:1,) A. fi—fi z—)l a3~1 X7i (9e / (l2x+574~E) B i ’ x/S fig,” 27C+5 4 2 «~71 <94 4><m+m 0‘ W = @w 2 D‘ flfi 5— "” M<l2X+5 A“) 1 3 2 .. 4 @W H+H JET 10. If f and g are continuous at x : 2 with 9(2) 2 3 2f($ )—39($) _ n i and z113% 2g($ ) fix) —7, the f(2) s 2gb) 3%(22) 3[2fil2) )dgl2)il :7 q<t2);1’+3(z)—le3 A. undefined .le 3 7 C. — — 3 D. :1 E. impossible to determine Q 3; 1 — 4x2 + 7x3 11. l' —— — \ z—iI—noo 28x3 — 7m + e “ B. . 4 ,{ ‘ : —g :3 T s A. C. - 2 D. E. 12. The total number of asymptotes, vertical and horizontal, for A the a hoff(x) (3‘2 ' . , r : —— IS g p \/ 2:02 + 750 + 3 B. l .. 1,1“; M X’“§. @ begin-441% 4‘7 .3 1- ac...» “M 2+ 3;: r .532 5 Coll—l ptxlr—I l0 [\Dll—l 13. If a ball is thrown directly up from the ground with a velocity v0, then A. 120 its height above ground at time t is given by H (t) : vot — gtz until is falls back to the ground. Here 9 is the acceleration of gravityt Then, B. 39 the velocity of the ball when it hits the ground 1s2 29 pix. w'ZZJIV TcL.m: fi/J 2g ‘ if 120 a, Hm— Mai») . «gm; 3, ). Q Tag/g zgt—AUQ “$912321? 2W~—2flr/)j: a 32 2h — 1 ' _ 14- fl(a) = gig) (—hl represents thgderivative of — ‘32 and (1—0 _* a certain function f at a number a in its domain. B f(x )_ _ 32. 2x and (1— _ 2 Determine f and a. 25 f(1; ):2m nda=5 g(a): am” 25 @( a vao R, D. f(x):2“’anda=32 QAS 5 :fl/m/ 2 ___—2‘? _ 1 E. f(x) = 32 and a = 0 Kata R] J: 15. Ifr + 38 + 1 = 0 is the tangent line to 7‘ = 9(5) at A. g(—1)= 2 and g’(—1) : 3 (— ,2),then \DR/ :{ivmfir'fl ,. i“&% B, g(2)=—1andg’2:() 3 (2/ “E3 s j _. i ‘— _: 1 g Z (. A) (s ‘l‘ Jl) fi FL 5 (’4‘)? E C. g(—1): 2 and g/(__1) : _é ’ fly} ”7’ 63H) + a(—1)+2:l my D- 9(2) = —1 and g'(_1) : 3 7 I %\~\4):-3 4M5 3%!”st @g(—1)=2andg'(—1):—3 ...
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