Sol-161E1-F2009 - MA 161 EXAM I Fall 2009 1 The interval...

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Unformatted text preview: MA 161 EXAM I Fall 2009 1) The interval which corresponds to the values of CE satisfying |3zt — 2| < 5 is m§< 3XW3~<$M A)(1,3) “if 1231:; MsBM— 17/3) / X1? CW] (“w/,1 “3/ D)(17/3] E)l13:l 2) The center and the radius of the circle represented by the equation 312+ 3y2 — 3:5 + 2y 2 1 are respectively “30¢ ”Xv/W4“? +%gg+:) $1+§+§ A)(1/2,1/3)and5/6 .fi. QM "fry?" B) (1, 2)and4/9 3f€kf§f +42%?) 9.] 11 [9‘ + C)(1/41)and5/6 xii: W5)D)(1/2,—1/3)and5/6 /;1 E) (1/2, —1/3) and 7/6 “\r—W 5” 2_ ”:1le [we ) 5%; 1.: 2:1] C{W'/‘1/W—f;&), V3575 MA 161 EXAM I 4) The domain of the function f (21:) : «jg: is W égjmé .2 > x A) [—33,] ””3 B) [—372) C) (—3,2] D) (—3,2) E) [—3,2] 5) Let f(:c) : $2 + 1, g(a:) : 2‘” and h(a:) : $3. Then f o g o h(a:) is equal to if: (?[A (ML) :$(Qy?) A) (2w)2+1 ,1 B) 26w+1 37(ng “f/ WW) C)4‘”3+1 a M 2-K D) 23$+1 4m 2 :/ E) (m3+2m)2+1 Z: 4/ “’44 6) The graph of f(a: —« 2) + 5 can be obtained from the graph of f(:c) by A) Shifting the graph of f to the left by two units and downward by 5 units B Shifting the graph of f to the right by two units and downward by 5 units D E ) M C) Shifting the graph of f to the right by two units and upward by 5 units ) Shifting the graph of f to the left by two units and upward by 5 units ) Shifting the graph of f to along the diagonal by 5 units Fall 2009 MA 161 EXAM I 7) The quantity 10g2 3 + 2 logz 5 + loge, 9 is equal to Fall 2009 T: Q :1" .22 C) logz 500 fi/éfia ["3 3’???) 3/4079? D)10g2700 E) 105.352 900 w A627 .1. (3 w 2 8) The inverse of the function f(:z:) : 2:1: is f”1(:c) : 9W r Y :2 fl :3- #0 w .' A> 39:2,; 3§f7 2 3m + 5 ”‘9 B) 7— 3:3 3W7» Sew C) ~7>c+3 :g/m‘ax) 5—39; 750 — 3 a 2—: 7x1: D) 5—395 5:; )6 793+?) 3 ? E) 5 _ 3:1: 9) Evaluate hm 3x2 — 48 if it exists. (If it does not exist, ar—>—4 a: + 2:): — 8 choose the answer DNE.) A) ‘4 3: r :3 (xi/10) z ’ 35% Mai") B) -3 WWNWM 3?: 47/ (W banal) C) 3 AN? “’7’ 657%) fix-«>1 ? ) Wm; D 4 :1” LEW“? :’ «.32; E) DNE Mb “”60 :9: 4% MA 161 EXAM I Fall 2009 Vt 1 — 2 10) Evaluate ling), ———%+T, if it exists. (If it does not exist, choose the answer DNE ) g A) C) 0 / :74 ’ [{‘twé’f/j , mm D)oo 79‘"; 3 "Ewe/s“) (12:; «7% E) DNE W I W ,2 ml“ rafl ?” 11) Let a: lim (x2 —a:) and [)2 lini) (:02 —msin%) Evaluate a and b. (If the limit does not exist, Choose DNE.) A) a : 075 :0 w. / 42m (wafl'f /m XV/ 31:3) 4% B)a:—oo,bDNE XPWO C)a=0,bDNE WW [\c kaxh:)fflm xflv 3m D)a=oo,bDNE wee y >5> WfiEM=omb=0 ”“0 5% Sfflf’fzvé %w. 12) The total number of asymptotes, vertical and horizontal, for the graph of 9:132 + 1 , f(:c)=———;——1s: AH) Awe/CE flWm/M“ My”! \lélv: B” A” 7‘50 (3)2 «25% m 2: W}; 3/, m k‘@% )(WB’M ”1334 /% ngaflg fir LLVQBf/xgzwg? ¥”9“M X‘M wax» 3" VJZWTL, a YXgm/JMM’ 2) X435? @ MA 161 ' EXAM I Fall 2009 13) For the function F (cc) pictured, Which of the following statements are true? 1.1im 17(30): 2 $60 11. lim F(a:)=0 a:-+2“‘ III. F is continuous at X20 MW? A) I only Z 717%“ B) 11 only gf’ /W C) I and II only [17“ /W D) 11 and 111 only ) E All are true 1 COSIE— 5 7r , represents the derivative of some function f(a:) at some 14) The quantity, lim x—rg- 17 3 number a. Select an appropriate f(X) and a. £(M)GWV fl[%)$§mg'wcj« A)f($ =cosm—%,a:% ) B)f(x :COSx—%,a:fl- a “7‘12? 3 We once ...
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