ph132s06_hw8 - Cl» 2‘3 3"" LMO 29—...

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Unformatted text preview: Cl» 2‘3 3"" LMO 29— SH" trim HOMEWORK # 8 Assigned: 03/06/06 SO SHEETS 22-]‘2 100 SHEETS 22-144 200 SHEETS 22-14! @ ' N072": : 7367:? 1‘3: kt _—_———’ 3'13: 0 25. Va: ; 2.0xro‘ 5 V7 - 30MB 1% Ex 1: I 50 SHEETS 22-142 100 SHEETS 22-1“ 200 SHEETS 22-14! g 'Anelecmismlcmwdfiommubyapotenfialdificw of 350 V. It then enter: a unifom magnetic field of magmde 200 mT with its velocity perpendicular to the field. Calculate (a)lhcspeedoflhcelecnmmd(b)thcmdinsofitspafl1inmc magneficfield. " 5;," unhszsnev}: THE” ScEAMRID Mam... EtAwn DIFF. ...” fl 5M9 THEM Mus? BE A» 225* .exac mfg—#— 3:» WE FIW‘EEQDNL EEC-Aug “THIS. rs AM away-Juan, 4-1" WILL MOVIE-7 :1» A >12. offosflz To “N45: 15:1. 0; E. 6c: V AMb 2" Ana AnTl-PA‘ZAMEL H5322. NbTEl '"N THE” 65'wa 725610“ TH£R£ :E'é A Mengfi (- Hm. __' _"'_"_ Esra: HER-E V' B B A12: fimmbmum‘k . (n ® 50 SHEETS 22.142 I00 SHEETS 22 144 200 SHII‘I'S 22-14! 111 Fig. 29-34. a charged par- ticle moves into a region. of uni- form magnetic field 3. goes mmg‘h half a circle. and then ex- its that region. The particle is ei- ther a proton at an electron (you must decide which). It spends “"29'“ mm“ 28' 130 as within the region. (a) What is the magnitude or E? (b) If the particle is sent back through the magnetic field (along the same initial path) but with 2.00 times its previous kinetic energy, how much time does it spend within the field? 50 SHEETS 22 I41 100 SHIITS 22-144 200 SHEETS 224‘! In a certain cyclotron a proton moves in a circle of radius 0.50 m. The magnitude of the magnetic field is 1.2 T. (a) What is the oscillator frequency? (b)Wha1 is the kinetic energy of the pro- ton. in electron-volts? osaum-ozv PW. 50 3mm 22-1‘2 IOO SHEETS 22-144 100 SHII'I'S 22-141 - _ Em prevent the cylindc: from rolling down a plane inclined FIgmeZQ-SSdnwsawmd cylhldadmassm=a250kg . IndlengflIL=0.lwm,with Nsionmmsofwinmapped 1" mnditlongimdimlly.mm mcplaneofdnidremilmmains ,_ menisoffllecylinder.WhaIis ' ' I Iheleastcmmifl'n'oughmcooi] “ wgleemdwhmimminmepmmofamdcd.mfifonu _ ~ tic field of magnitude 0.5001. ifthcplane oflheooil is Wlmflwmdimdphnc? m 22 MI 50 SHIFTS 22-142 100 SHEITS 22-145 200 SHEETS __L -. 1 .Ol‘l - _. canyingacunentofSD A.isind|cslnpeof 7 ' .- ‘ = Wfimsidum.w.mwcm.mmkma L 5 magnet“: field of magnitude 80 111T Whose direction is E): SDI/0‘5 7- 62 = 30% =0.30M b: 40% ’0. VOM C: 50046 0.50M 60/0 b)? b A hpokboddffhpajc sotu'hb” dbok mm and 4073-: 61) h»: M51217) AF] (0M5 Ila-op) 63: an: 6r “HM Mdjmi‘td? 0131]”: flag/4 ‘66,)0-5 ._ _ . . . =5m>é(o.sm>(0-4m) Nate : I? is Aim/idea éméfi'c 19M”? m Am“ = Ans. of ‘4: 77m curred (WW m and firm, beam 13‘ :3 msf Wed :6 W #6 WWII“. W! hart Manta/W (5‘ 1:5 (wanra/Dcwfl', Mum A word'mé .Cffivaa" (IS in .4 #rsam dream ant/i". lTfiaWIer-sh +1» ~12 or (e. damfian. can a n‘ film/rack, Wm m fig”: :11 I mm» 031‘}! grim, oar #mflm He d/rmfbr ior’ Pin/fl“ -' k- ;b) grfixs 7r"’=~*x = (22:51” 5(é‘x2‘) 13*?” fl ‘3 /“ f.‘ ._ J Fgaaj‘ - I ABCDEFA can?“ __ Clive” -' LI: 5-00 A ~ ~ I " “m'dmmm' ‘- ‘-- . AB: 20.0m:0.200u1 dinalcaxcs, withAB = 20.0m.BC = 30.013111. and FA =, 10.0 cm. Cam-1m the magnitude and dimion of the magmatic; 8C: ow ; 0.300,“ dipole mat of this loop. (Him.- Imagine equal and oppositc‘ entrants 1' in the linc segment AD; then that line two rectangular loops ABCDA and ADEFA.) RF /0-0 cw OJOM Phr/if’fir ABCDEFA 50 SHE"! 11 I42 100 SHEETS 22444 200 SHEETS 22-141 5 “3’ 2 ,L a. flflmpfl fiBfib fl.”be ' fl: Air” =6‘A (Na!) " :‘(ABYBcX-DH {FAXBoj (15¢ #m n’ M had m/e 153 361‘ f6: indies gr {£65}? fl" = {5.0035(0.100M)(0.300M)j -(s.oon)/a.2ooM)(o.sooM)p, Akbam : 14l._ ‘ z - (QED/Quad 0-300flmk ANS. WI: 0“ (/.50AM=-)2 + (0300,4sz 2 a 335AM2AMS‘ .. ~03 - _ , 6:157:71 o.z;:)‘ {54% 717—5 p/am Ms. AlmgthLofwirecan-iesaumtijhowdmifdm -L fanned into a circular 0061, then the maximum torque in a ,3: 50 SHIETS 22-112 ‘IOO SHEETS 22444 200 SHEETS 22-141 (9% . 4 magnetic field is developed when [he cod has one turn only, that maximum torque has the myfitfldfl 1' = 1.2.3:“. m; L . 4—- ‘n‘ 22: .5. : Z’Trz Er;- ._. L zurN "THE ARE'A 0F Ekch‘ Loop IS THUS A _— «22 L z W (INN L7. - I'mrmz WHEN CARKY’MG’ CURRENT I THE Mema‘fir. DIPOLE Mom? MT VECroTL «.739. =NiA z N l. 0 Z I m. n5 cw. '12 l4! 50 SHEEYS 22-142 100 SHEETS 22 144 200 SHEETS 5) ’1'" =flx§y53w70° 718 =A/L‘AB anrzB -'slafimurychcularwallckx:khasafaoc withanldiusof ' '1' Sixmmofwiremwounduounditspuimam'fiwwim ---Icwru1tof2.0AinflIeclockwisedirection.1hcclockis - whaclhmisaoonstanguniformcxlcmaluugncficfield -='_r;u -- mm'rmutmeclocxsuukeepspcrrmmLm _1:oop.m..mehomhmdonheclockpoinumundimcdon term! Wficld. (a)Afln‘howmany minutes willlhe "'1': poimintlwdimclionofmcmtquconthewindhgdm u ' field?{b}Fmdlhelorqucmngnimde. arr-“0.15M . _i ____ __.~¥_ : "-:@'ven - r: 15 ' _ N3 (0 -, £7.20)? clockwise. - 8-" 70mT= 70 x/o‘5T alung w/ 1 | 511g}: 0:.) dt'recmn of 7" i I I l } b) magmyxde 0(- ‘F’. oa'nfsAihfo 241: page 6:: mafia” in ca zQ-GG) 95,: 53‘ A =_/M5 1, 77M mafia/f ill/III 1017/ pair} I?! {fie c‘aé'fecm dig? M3. _ = Mum)rr(0.:5m)“(7ox/o-3T)—mus. 22-14! 50 SHEET! 22-142 100 sum: 22 I“ 200 SHEETS Q present. given by milliteslas. Calculate the fame on the 2.0 m segment of the con- ducmnlmliesbemeenx = 1.0111311: = 3.0m. Wilda 511’. A long. rigid W. lying along Ihexuis, carries a mlofSDAind-lemgatindimcdon. Amngneucficldnis 3:3.0i+8.0x1j,wilhxinmmand3in Canada/a smail sejmnf dz : d§= Idl’xl? d F?*'fdx€" Fl? 01?: win“ Mk “bW-MC {bin/firm befiwnaqd'na/a’zl Fab 2‘: A _ ’3 F5 =j-"dx::xg”= L dX(~£’)><_(3.03+g.0x=“) K, - 3 ' (5.0 A)(?.om'r 3 yawn)” * (wufjc ’ Aug. 0’? 3's (h #z 30;»: driffcfib? as HR canard: ..._- .__.., . ..._ ._..._— “mm-F...— PH 132 Suggested Problems ...
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ph132s06_hw8 - Cl» 2‘3 3&amp;quot;&amp;quot; LMO 29—...

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