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Unformatted text preview: Version 056/AADCA – QTest #3b – Antoniewicz – (56495) This printout should have 2 questions. Multiplechoice questions may continue on the next column or page – ﬁnd all choices before answering. 001 10.0 points Four charges are at the corners of a square centered at the origin as follow: 7q −3 q −8 q −6 q at at at at (−4 a, +3 a) , (+4 a, +3 a) , (+4 a, −3 a) , (−4 a, −3 a) . 32 k ma Explanation: The initial energy of the charge is 9. v = q Ei = Ki + Ui = Ui = and = = 2 (−7 q ) V0 m kq (7) + (−3) + (−8) + (−6) 5a (−10 q ) k . 5a 1 A ﬁfth charge −7 q with mass m is placed at the origin and released from rest. y 7q −3 q 3a 5a −7 q, m 4a x The ﬁnal energy is Ef = 1 m v2 . 2 From energy conversation, we have Ei = Ef 1 (−10 q ) (−7 q ) k = m v2 5a 2 −6 q −8 q v=q v=q Find the ultimate speed when it is a great distance from the origin. 1. v = q 2. v = q 3. v = q 4. v = q 5. v = q 6. v = q 7. v = q 8. v = q 20 k ma 24 k ma 36 k ma 30 k ma 28 k correct ma 34 k ma 64 k ma 40 k ma keywords: 2 (70) k (5 a) m 28 k . ma 002 10.0 points A parallelplate capacitor has a capacitance C0 . A second parallelplate capacitor has plates with twice the area and twice the separation. The capacitance of the second capacitor is most nearly 1. 1 C0 . 2 2. C0 . correct 3. 1 C0 . 4 4. 4 C0 . Version 056/AADCA – QTest #3b – Antoniewicz – (56495) 5. 2 C0 . Explanation: A′ 2A A = ǫ0 = ǫ0 = C0 . ′ d 2d d 2 C ′ = ǫ0 ...
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This note was uploaded on 10/01/2010 for the course PHYSICS PHY 303 L taught by Professor Antoniewicz during the Spring '10 term at Texas Pan American.
 Spring '10
 ANTONIEWICZ
 Physics, Charge

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