SolnsChapter3

SolnsChapter3 - 2 mʬÊ=ÊdÊsinÊœ ´ m ¬ = d...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2. mʬÊ=ÊdÊsinÊœ ´ m ¬ = d sinÊ35‚ = 0.574 d. ¬/d = 0.574/mÊ. “Only” ‡ mÊ=Ê1. So ʬ/dÊ= 0.574 3. ¬ = h/p = h/mÊc = 6.63¿10-28 kg˛m/sÊ/(9.11¿10-31 kg)(3¿10 8 m/s) = 2.43¿10-12 m . 4. qÊV = ªÊmÊu¤ = (mÊu)¤ 2m = p¤ 2m = (h/¬) 2 2m . Solve: ¬ = h √ 2ÊmÊqÊV 5. p = h/¬ = 6.63¿10-34 J˛s 10-6 m = 6.63¿10-28 kg˛m/s. u = p m = 6.63¿10-28 kg˛m/s 9.11¿10-31 m/s = 728m/s . This is actually quite slow as free-electron speeds go. 8. KEÊ= p¤ 2m Ê´ 1.6¿10-13 J = p¤ 2Ê(1.67¿10-27 kg) ‡ÊpÊ=Ê 2.31¿10-20 kg˛m/s.Ê 6.63¿10-34 J˛s 2.31¿10-20 kg˛m/s Ê= 2.87¿10-14 m . 20Ê¿1.6¿10-19 J = p¤ 2Ê(1.67¿10-27 kg) ‡ p = 1.03¿10-22 kg˛m/s. 6.63¿10-34 J˛s 1.03¿10-22 kg˛m/s = 6.41¿10-12 m . 10. p = h/¬ = 6.63¿10-34 J˛s 10-9 m = 6.63¿10-25 kg˛m/s. u = p m = 6.63¿10-25 kg˛m/s 9.11¿10-31 m/s = 7.28¿10 5 m/s . (b) Using result of exercise 4, ¬ = h √ 2ÊmÊqÊV ´ 10-9 m = 6.63¿10-34 J˛s √...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online