MAE305_pset05s

MAE305_pset05s - M&AE 3050 Problem Set 5 Fa 2009...

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Unformatted text preview: M&AE 3050 Problem Set 5 Fa 2009 Solution 1. Problem 5.2 in Anderson. Solution We assume a Standard Atmosphere for the gas. The problem parameters are as follows ρ ∞ = 2 . 3769 × 10- 3 slugs , v ∞ = 100 ft / s , T ∞ = 518 . 69 R , a ∞ = p γRT ∞ = p (1 . 4)(1716)(518 . 69) = 1 , 116 ft / s , M ∞ = v ∞ /a ∞ = 100 / 1 , 116 = 0 . 09 , c = 3 ft , W = 1 ft , α = 5 ◦ . The coefficients for lift, drag and moment are (from pgs. 858 and 859 of Anderson, ignoring the effect of compressibility since the Mach number is so small) c ‘ = 0 . 65 , c d = 0 . 007 , c m =- . 025 , yielding the following forces ∴ L = c ‘ 1 2 ρ ∞ v 2 ∞ cW = (0 . 65)(0 . 5)(2 . 3769 × 10- 3 )(100 2 )(3)(1) = 23 . 2 lb , ∴ D = c d 1 2 ρ ∞ v 2 ∞ cW = (0 . 007)(0 . 5)(2 . 3769 × 10- 3 )(100 2 )(3)(1) = 0 . 250 lb , ∴ M = c m 1 2 ρ ∞ v 2 ∞ c 2 W = (- . 025)(0 . 5)(2 . 3769 × 10- 3 )(100 2 )(3 2 )(1) =- 2 . 68 lb ft ....
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MAE305_pset05s - M&AE 3050 Problem Set 5 Fa 2009...

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