{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

6 - Copy (2)

# 6 - Copy (2) - Version 019/AABAD inclasstest 02...

This preview shows pages 1–2. Sign up to view the full content.

Version 019/AABAD – inclasstest 02 – turner – (56705) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 3) 10.0 points An electron traveling at 2 × 10 6 m / s enters a 0 . 09 m region with a uniform electric field of 168 N / C , as in the figure. The mass of an electron is 9 . 10939 × 10 - 31 kg and the charge on an electron is 1 . 60218 × 10 - 19 C . - - - - - - - - - 0 . 09 m + + + + + + + + + ˆ ı ˆ 2 × 10 6 m / s Find the magnitude of the acceleration of the electron while in the electric field. 1. 11608200000000.0 2. 34121100000000.0 3. 47136400000000.0 4. 29548200000000.0 5. 30955200000000.0 6. 39221700000000.0 7. 20226400000000.0 8. 40101100000000.0 9. 18643500000000.0 10. 21809400000000.0 Correct answer: 2 . 95482 × 10 13 m / s 2 . Explanation: Let : q e = 1 . 60218 × 10 - 19 C , m e = 9 . 10939 × 10 - 31 kg , and E = 168 N / C . F = ma = q E , so vectora = - q e E m e ˆ = - (1 . 60218 × 10 - 19 C)(168 N / C) 9 . 10939 × 10 - 31 kg ˆ = - (2 . 95482 × 10 13 m / s 2 , and the magnitude of the acceleration of the electron is 2 . 95482 × 10 13 m / s 2 . 002 (part 2 of 3) 10.0 points Find the time it takes the electron to travel through the region of the electric field, assum- ing it doesn’t hit the side walls.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

6 - Copy (2) - Version 019/AABAD inclasstest 02...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online