PH101 HW Momentum

# PH101 HW Momentum - This print-out should have 16 questions...

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Unformatted text preview: This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points Calculate the momentum for a 0 . 3 kg rifle bullet traveling 500 m / s. Correct answer: 150 kg · m / s. Explanation: Let : m = 0 . 3 kg and v = 500 m / s . p = mv = (0 . 3 kg)(500 m / s) = 150 kg · m / s . 002 (part 2 of 4) 10.0 points What momentum does a 1000 kg automobile traveling 0 . 5 m / s (a few miles per hour) have? Correct answer: 500 kg · m / s. Explanation: Let : m = 1000 kg , and v = 0 . 5 m / s . p = (1000 kg)(0 . 5 m / s) = 500 kg · m / s . 003 (part 3 of 4) 10.0 points What momentum does a 70 kg person running 9 m / s (a fast sprint) have? Correct answer: 630 kg · m / s. Explanation: Let : m = 70 kg , and v = 9 m / s . p = (70 kg)(9 m / s) = 630 kg · m / s . 004 (part 4 of 4) 10.0 points What momentum does a 19000 kg truck trav- eling 0 . 03 m / s (a slow roll) have? Correct answer: 570 kg · m / s. Explanation: Let : m = 19000 kg , and v = 0 . 03 m / s . p = (19000 kg)(0 . 03 m / s) = 570 kg · m / s . 005 (part 1 of 2) 10.0 points A moving object has a kinetic energy of 147 J and a momentum of 33.5 kg · m/s. a) Find the speed of the object. Correct answer: 8 . 77612 m / s. Explanation: Let : K = 147 J and p = 33 . 5 kg · m / s . p = m v K = 1 2 mv 2 = 1 2 p v v 2 = 1 2 p v Thus v = 2 K p = 2 (147 J) 33 . 5 kg · m / s = 8 . 77612 m / s . 006 (part 2 of 2) 10.0 points b) Find the mass of the object. Correct answer: 3 . 81718 kg. Explanation: m = p v = 33 . 5 kg · m / s 8 . 77612 m / s = 3 . 81718 kg . 007 (part 1 of 2) 10.0 points When the velocity of an object is quadrupled, by what factor is its momentum changed?...
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PH101 HW Momentum - This print-out should have 16 questions...

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