Homework 6 (Chapter 9)

# Homework 6 (Chapter 9) - (d SeCl 6 Octahedral Michael...

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(d) SeCl 6 Octahedral (e) PF 5 Triangular bipyramidal Michael Yagudayev106180606 CHE 131 R01 Homework 6 – Chapter 9 C9 Problems: 13, 15, 21, 23, 38, 40, 44, 48, 55, 58, 62 13. (a) BeH 2 H – Be – H (Linear) (b) CH 2 Cl 2 Tetrahedral (c) BH 3 Triangular planar 15. (a) PH 4 + : electron geometry – tetrahedral; molecular geometry – tetrahedral (b) OCl 2 : electron geometry – tetrahedral; molecular geometry – angular (c) SO 3 : electron geometry – triangular planar; molecular geometry – triangular planar (d) H 2 CO: electron geometry – tetrahedral; molecular geometry – triangular pyramidal 21. (a) O—S—O angle in SO 2 = 120° (b) F—B—F angle in BF 3 = 120° (c) 1 = 120° ; 2 = 180° (d) 1 = 109.5° ; 2 = 120° 23. (a) F—Se—F in SeF 4 = 90°, 120°, and 180° (b) O—S—F in SO 4 = 120° and 90° (c) F—Br—F in BrF 5 = 90°and 120° 38.

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-- The first two C atoms are sp 3 hybridized with 109.5° angles. The third C atom is sp 2 hybridized with 120° angles. The N atom is
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Homework 6 (Chapter 9) - (d SeCl 6 Octahedral Michael...

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