Homework 9 (Chapter 10)

Homework 9 (Chapter 10) - Michael Yagudayev 106180606 CHE...

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Michael Yagudayev 106180606 CHE 131 R01 Homework 9 Chapter 10 16. (a) 720. mm Hg to atm . × = . 720 mm HH 1 atm760 mm Hg 0 947 atm (b) 1.25 atm to mm Hg . × = 1 25 atm 760 mm Hg1 atm 950 mm Hg (c) 542. mm Hg to torr . × = 542 mm Hg 760 torr760 mm Hg 542 torr (d) 740. mm Hg to kPa . × × . = . 740 mm Hg 1 atm760 mm Hg 101 325 kPa1 atm 98 7 kPa (e) 700. kPa to atm . × . = . 700 kPa 1 atm101 325 kPa 6 908 atm 24. Place in order of increasing average molecular speed at 25°C CH 4 < N 2 < Kr < CH 2 Cl 2 29. How many moles of CO are present in 1.0 L air at STP that contains 950 ppm CO? × × - / = . 950 ppm CO 1 10 3 g L1 ppm 0 950 g CO1 L = = . . / = . n massMolar Mass 0 950 g CO28 01 g mol 0 034 mol 30. If 50.75 g of a gas occupies 10.0 L at STP, what volume will 129.3 g of the gas occupy at STP? = = = . . . = . m1V1 m2V2 V2 V1m2m1 10 0 L129 3 g50 75 g 25 48 L 32. A gas sample has a pressure of 100. mm Hg in a 125-mL flask. If this gas sample is transferred to another flask with a volume of 200. mL, what will be the new pressure? Assume constant temperature. . × = . 100 mm Hg 1 atm760 mm Hg 0 132 atm = = = . . . = . × P1V1 P2V2 P2 P1V1V2 0 132 atm0 125 L0 200 L 0 0825 atm 760 mm Hg1 = . atm 62 7 mm Hg
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This note was uploaded on 10/03/2010 for the course CHE 131 taught by Professor Kerber during the Summer '08 term at SUNY Stony Brook.

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Homework 9 (Chapter 10) - Michael Yagudayev 106180606 CHE...

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