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Unformatted text preview: m × n matrix A to be L v 1 . . . v m = L ( v 1 ) . . . L ( v m ) = A w 1 . . . w n Let (¯ v 1 ,..., ¯ v m ) to be a new basis of V . Deﬁne the associated m × n matrix A new to be L ¯ v 1 . . . ¯ v m = L (¯ v 1 ) . . . L (¯ v m ) = A new w 1 . . . w n Then A new = BA, where B is the m × m basis change matrix from ( v 1 ,...,v m ) to (¯ v 1 ,..., ¯ v m ) , i.e. B v 1 . . . v m = ¯ v 1 . . . ¯ v m 2...
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This note was uploaded on 10/03/2010 for the course MATH 223 taught by Professor Loveys during the Spring '07 term at McGill.
 Spring '07
 Loveys
 Linear Algebra, Algebra

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