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Unformatted text preview: and p ( A ) is its inverse. (b) The two matrices from exercise 3.30 were A = 4 22 3 and B = 22 2 1 1 1 . We found there that with q ( x ) = x 27 x + 16, q ( A ) = 0. In this case, q (0) = 16, and q (0)q ( x ) xq (0) = 1 16 (7x ) . Therefore. by part (a) , A is invertible, and A1 = 1 16 (7 IA ) = 1 16 32 2 4 . 21 /september/ 2005; 22:09 29...
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This note was uploaded on 10/03/2010 for the course MATH 380 taught by Professor Gladue during the Fall '08 term at Roger Williams.
 Fall '08
 Gladue
 Calculus, Matrices

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