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IRWIN 9e 14_10 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E “$.10 Fiml malt}. I El. iii the network F-JIL‘JWI] in Fig. F'lLHIII 1.15nglltlLIEll-Llllulyrlifi. ‘Ifl firilr} ‘-.-’ : Figu re Piano SOLUTION: Problem 14.10 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin, Basic Engineering Circuit Analysis, 9/E Eda-W: Vz>(9‘\/5(5) Jr V06) M '1 j. i 1 \4? (9%“) -- s (VoU)—\I3(§))+\/°(S) (8 n) V06) = M9“ V35) Srlvazi’: i—i. s 5.54; ()0) 3+3 \Sfl-r-[Z SH (“IN/0(5) /6 a i 4' + 6 -_ 4’3 :7 Jr/ 5"" (3+2)VOCS): 1&(S—H)— 41 + £5 (Jr/)- 4-5 2‘ KOCH) ’ (3+2)VD(S) ' )8! +- I8‘ 41' ‘f’ 61 L‘f‘éK-4'J 2’ \ «5+0 my (WW/08) - 33253214? ‘ $(5-H) (m +2)Vo(s); (4!r>&9) M saw) V0 s) _ My.“ £(s+r)(&+—2.) QM») 02 (J—r?) :3 A + j.— 2(1+9)=' A (“'39) 1' 3‘ Md: ~9— JLO): ~28 ; - 1 Problem 14.10 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin, Basic Engineering Circuit Analysis, 9/E 3 1&1: 3:0 18; 2A A: 9 V08); g. - 5?: + ___—__—__—__—_——-———————-—-—— l Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.10 ...
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