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IRWIN 9e 14_14

# IRWIN 9e 14_14 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 9/E 1 1.1.1:; For the network shown in Fig. 1314.14, ﬁnd 1:40,: 3:- ﬂ, using mash equations. Figure P1444 SOLUTION: KCL: 11(5) : 1”“) + 13(3) 10(5) 2 12(5) ~ 130) 34%. = i L—I’cs>)+211(2)+ i (1%”) _ (I‘ls)~1;(s))+,zllg) +~ Mam-:14” =..- fig “LC-9+ 411(3) —-13(s) 2» 4/3 KVL‘. KVL'. i (—I",(s)) + 313(3) + l (15(9) = 0 " (1.2“) ‘13”) + (3+!)I3cs) = a ~Iicg) + {s+.2)13(s) :2 0 I2 (3) 2 (\$450133) Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.14 E Problem 14.14 lrwin, Basic Engineering Circuit Analysis, 9/E Chapter 14: Application of the Laplace Transform To Circuit Analysis ...
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IRWIN 9e 14_14 - Irwin Basic Engineering Circuit Analysis...

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