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IRWIN 9e 14_31

IRWIN 9e 14_31 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin. Basic Engineering Circuit Analysis, 9/E 1 a 1.15.31 Find igier E]. in this neiwnrk shown in Fig. P1431. (I 1 F 1 ﬂ lair} 3i} Figure Fig.31 SOLUTION: KCL'. Ilaﬁlmﬂy) 1(3) 3 1,0) —- 102a) 1 Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.31 2 Irwin, Basic Engineering Circuit Analysis, 9/E KVL'. v 0‘28 1‘C5)+<l‘l'3) 115): o 15 (Laylng 4x13): 0 .. (Rs 11(S)+L2\$ ‘— 4) ILL\$)=O asl’a): (§?\$+4’) ILLS) I'ls): 32-2. 11(3) xiii) rig—\$129): - 8,3 1:2“)[08 L-l- 4': +081? ’353] z ’3- S" J “loo If) a“ 3+ 4323M + +\$L+83+ Q-o?s_3]=- 3)- iv Ills>[§s:jjx_:i] .- 1; S E Problem 14.31 Chapter 14: Application of the Laplace Transform To Circuit Analysis Irwin, Basic Engineering Circuit Analysis, 9/E t: "’13 1' JU/a)’; 4.0%“ cm) 3: —ov 5&25’ + 0.2571 10(5):. _____.~_S_______._,_,..,_..W (4+ mu.) (90.31) 13(3):— ...f).....__..... + ’3 J+O.82_ J+0'3/ 3: AC” 0.3l)+ f5 [ts-rota») MJ: —0~3I —o-3i; Idea-31+ 043;) l3:—0'6/ lax; —o-82 ~ o~8z; AC—D'KZTOISI) Azl-GI __ “0-82 ~no.3) _ . — 043M“ 400(t) : 1.61.: o 825 a. GM, ju(f}A Chapter 14: Application of the Laplace Transform To Circuit Analysis Problem 14.31 E ...
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• Fall '10
• MicahStickel
• Circuit Analysis, Basic Engineering Circuit, Engineering Circuit Analysis, Irwin. Basic Engineering Circuit Analysis

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