IRWIN 9e 11_8

# IRWIN 9e 11_8 - lwvin, Basic Engineering Circuit Analysis,...

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Unformatted text preview: lwvin, Basic Engineering Circuit Analysis, 9/E 1 11.8 Find this equivalent I n[' the netwm'k in Fig. P] 1.3. 2H H 211 an —'1n.-" (DJ—Hi1 ii Figure P113 SOLUTION: a, Chapter 11: Poiyphase Circuits Problem 11.8 2 Inn/in. Basic Engineering Circuit Analysis, 9/E {11' ivT i3 2;. i4» 1911*i'ji ’ 5 L«56.3°n 1a, = 0‘ 5 .. ‘ ‘ 3’10) 13 gs» {fin Problem 11.8 Chapter 11: Polyphase Circuits Irwin, Basic Engineering Circuit Analysis, 91E 3 "z’ = [32 Man (21W) 9} is (0. 3°} L—n.a°-.—44ji)(o.39L-’H'3°nn]l) WETETTTWWO. sci 1.”. 5012.31 '+o.551—56.3°¢2. f: 3569 Lama Chapter 11: Polyphase Circuits Problem 11.8 ...
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## This note was uploaded on 10/04/2010 for the course ECE ECE212 taught by Professor Micahstickel during the Fall '10 term at University of Toronto- Toronto.

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IRWIN 9e 11_8 - lwvin, Basic Engineering Circuit Analysis,...

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