IRWIN 9e 11_42 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E ____________________________________.__. 11.42 In ;t balanced three—phuae ayatent. the {the—11mm— Ht‘quenee atiuree i5 Wye etinneeted and van = 120 .320" ‘v’ “TH. The lead emmiratr: ni' twn hatt- uneetl wees; with phase nnpedaneen nt' 8 + jfl fl and 12 + j?- &1. It the line impedance is; xern. i'iml the line currents; and the phase current in each lead. ____________________._.—— SOLUTION: flan: lat) L§<0° \/»tm3 fl = 8+j25» L: \Q-i- jbn. Problem 11.42 Chapter 11: Polyphase Circuits Irwin. Basic Engineering Circuit Analysis, 9/E I”: 29.25 [:me Aams ICC = 2“" 2‘3- L’25’ ‘79“ A 9;"): _____________________._____—————————————— Problem 11.42 Chapter 11: Polyphase Circuits ...
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  • Fall '10
  • MicahStickel
  • Electrical impedance, Basic Engineering Circuit, Engineering Circuit Analysis, Polyphase Circuits Irwin

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