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IRWIN 9e 11_45

# IRWIN 9e 11_45 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 ______________.______.__—————— 11.15.; In E: hatluneed three—phase system. the Ht‘tlll't‘t‘ has an] rifle—plume sequence and is; ennneetetl in delta. There are twn lntada ennneeted in ptu‘nllel. The line ennneeting the nntlree tn the JR'IﬂLlh' hue; an intj'tednnee nt' 0.2 + ﬁll 11. Lnud l in ennneeted 1'11 Wye. and the phnne impednnee in 4 + 1'2 ﬂ. Lnnd E in ennneeted in delta. and the phnrte impedance in 12 + _,r"§l IL. The current 11,15. in the delta Jnutl is 16 rth. Find the phage L'nltnge nt' the Ht‘tLll'Ci'. SOLUTION: Problem 11.45 Chapter 11: Polyphase Circuits 2 Irwin, Basic Engineering Circuit Analysis. 9/E \7 - lw 5‘5 Anzac" V/Lml AN " _. "‘ ,_ o in“: \iAN z .88'55: LgLBL? ZLt 4-i-J2- A 0 IRA ‘ 1AM‘T IAN; TM = 3) [35”. 3°+1?» 7/ 05:9 Im, 53. w Law/c," A 7m! KVL'. QM ; (0‘11-joo|)(58~97[_ao.9‘17+158-55151.84“ van: r5158 (5/45" vms \in = EMT/.58) 151.95” +3o° Vab= 2é2.§"/ L5I‘9‘50 Vtmr k V” ; 242. 5’9 4:38. 5'15" VFW b V“; 262.- 591—433.?5 VYMJ Problem 11.45 Chapter 11: Polyphase Circuits ...
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