IRWIN 9e 11_46

# IRWIN 9e 11_46 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 11.46 In a balanced three—phase system, the source has an nine—phase sequence and is connected in delta. There are two parallel owe—connected loads. The phase impedance of load 1 and load 2 is 4 + _.i4 [1 and 10 + j-ﬂ- [1, respectively. The line impedance connecting the source to the loads is 0.3 + ﬁll 11 If the current in the n phase of load 1 is I AMI = 101.320: A rnts, ﬁnd the delta currents in the source. SOLUTION: ZL‘ = 4" +j4‘_§L ZLL= lo+ ﬂit wa ,_ 06+ 30-29. ‘= ioQo°AAmg View 555? Légo \/ hm: iii-pad), : \IAer ; 56' 5} in (0+j4— 1M»: 5.25 [331° Aﬂms Chapter 11: Poiyphase Circuits Problem 11.46 2 Irwin, Basic Engineering Circuit Analysis. 9/E .n .a o f ’ O 5 IAN. + IAM>: \IO (30 .— IaA = \‘i'q? (31"5” pf 37m; 1:6, in} L30 A f5 ' 1' aw. 4" 30° «,5 J}.— L 9 + 1N3“ 869' LW-W/o A a’ms Fa- T fbc : L—{LIOAMY}: it = 8'69 Maw A 4m; Problem 11.46 Chapter 11: Polyphase Circuits ...
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• Fall '10
• MicahStickel
• Electrical network, Irwin, Electrical impedance, Basic Engineering Circuit, Polyphase Circuits, Poiyphase Circuits

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