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IRWIN 9e 11_50

# IRWIN 9e 11_50 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 __________________________._________.______ 11.5ﬂ .Jm trik—Hequeilee u-‘y‘e—emmeeteil anume having a phase—er voltage of 120 ‘v’ rim; is attached to ;1u-'}-'e-em1r1eetel.l lurid having 21 per—phase impedhhee hf 10037611. |[' the line impedance i5 1 3’20" {1. Lleienmne the retail eumj'IJex pnwer prmhleeil h}: the wit-age wureer: uml the real and reactive ham-er diﬁﬁlpﬂtn‘d h}: the hml. SOLUTION: flan g 12-0 w" v ms :r = 120L9° = Heb-6944 01A a m a 1010 + loo (3’0 53-¢ = 3(120d9”)(l~ )9 L694?) 428. 4— 1662.5 VA 5M =- a :0: sowwmmv = 1+6. 3+] 391m VA (A: \ a \I 3,¢ -= k3 Chapter 11: Polyphase Circuits Problem 11.50 2 Irwin, Basic Engineering Circuit Analysis, 9/E __—_—_—_.—.__——————————-————————— Problem 11.50 Chapter 11: Polyphase Circuits ...
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