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IRWIN 9e 11_53

# IRWIN 9e 11_53 - Inivin Basic Engineering Circuit Analysis...

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Unformatted text preview: Inivin, Basic Engineering Circuit Analysis, 9/E 1 11.53 In a balanced tlu'ee—phase “rye—Wife system, the source is an nine-sequence set nf vnltages and Van = liﬂfﬂﬂ” Vrms. The pnwer absni'bed by the lead is 3435 W and the load impedance is It] + 12 [1. Find the two pessible line impedances if the newer generated by the source is 3TH W. Tli‘ii'llliclll line impedance is mere likely.r tn nccur in an actual newer transmission system? SOLUTION: 1 gb gm _ lu:c PM: {>5 ﬂ? = lam—mg“ P ,_ Haw V lwm it”: PL :J ”95‘ ; )0.” EL. Chapter 11: Polyphase Circuits Problem 11.53 2 Irwin, Basic Engineering Circuit Analysis. 9/E SI - 30—“.55 =mt45° QR s» 3 - 30+ “.55" = M 55° IQA 53%, a ‘20 L330" - 004145-959) (twp) 104118.95” ~ —’v o .0 ’ Q 1 mean: mmm‘w ,urw, mpaolanm .. mm ,0. tej 6V), . f. = 220 L30: (m7 L4+ 5‘s“?(/p+]22 we [0:7 L4L55’J Problem 11.53 Chapter 11: Polyphase Circuits Irwin, Basic Engineering Circuit Analysis, 9/E 3 '“w * . .J . w M , ° _ Ziw ; O “i? J4’- 26. «Cormamxfmw; LmPcdcmw .a—u z,» 7. o-a‘iﬂmrm. it; mm waif, me. _______________.__.__._._————————-————— Chapter 11: Polyphase Circuits Problem 11.53 ...
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