IRWIN 9e 11_55 - Inivin Basic Engineering Circuit Analysis...

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Unformatted text preview: Inivin, Basic Engineering Circuit Analysis, 9/E 1 ———~———-———__.___—________________ 1.1.55 .-—'t. UJLIHEL‘I' trt' [trades are Herr-ed h}: a balanced three—phase HUUE'LIC with at line witttge 01' 4160 ‘v' rms. Ltmtl ] is; Edtl kit’s—"t. at (LE pi' lagging and 2 rs [ta-III kit’s—"t. at (L92 pt' lagging. .fit third [field is; ttnhndwn exeept that it has; Li pdwer ittetdr id unit}. It' the line eurrettt IiH- measured and i'nund tn he hi .-—‘t r1115. find the edmpie}; ]'ILWI"C[' 01' the unhttnwn Jihad. SOLUTION: “fab! = 4-160 \/ Mns LOfldi: k [GOA—i (0'8) 57;- 024—0 136.8?” km ‘1 Load 2: ; s 160 k Loot" (0-92) §L= I60 (023.0513) KVA i, : f3 (9160)(69—)= 996- 732mm 53—,- P3+jo PT= PM $13 8; (Qt/0k cu 36-57°=292_l<rd Chapter 11: Polyphase Circuits Problem 11.55 2 Irwin, Basic Engineering Circuit Analysis, 9/E P2; 16014 vac/1:25.076: “1‘1.ng PT: (worm-Par) kw QT3 Q1+QLT83 Qw AM a». 36.87u=m kw, __________________________._.__—————-——-—- Problem 11.55 Chapter 11: Polyphase Circuits ...
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