IRWIN 9e 11_59 - Irwin. Basic Engineering Circuit Analysis,...

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Unformatted text preview: Irwin. Basic Engineering Circuit Analysis, 9/E 1 11.59 A. inflamed three-phase soto'oe serves two leads: Load 1: so k‘w’A at I13 of logging Load 2: IS k‘w’A at or; of logging The line voltage at the load it; 2:13 ‘1? rros :tt 6:] HI. Find the [toe current and the combined power factor Ell the load. SOLUTION: O Loadi: 36 kVAmeoo PF/t LOMZ’, i8 KVA fir o.6 pp VL’; 208 V&mg sIP93 z 36 k Lam" (0'8) ; 12(56.8¥°/<VA 52 5 )8k Law” (0'6) age/9km I'd 3 z 3‘ z E + 5 — /2/< a .8 b ' ° THIS [Hp 2"?) _ La 7-1'6/(L53J3 S o TI‘q, = L42'21 Chapter 11: Polyphase Circuits Problem 11.59 2 Irwin, Basic Engineering Circuit Analysis. 9/E ERA : ng-'¢ :- W'BL‘kL-M'Zf * I205)" f 293434 L—42.2.7.° A mm m ‘ PP; «COX (/2. 2¥o= 0'74“) Problem 11.59 Chapter 11: Polyphase Circuits ...
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