IRWIN 9e 11_60

# IRWIN 9e 11_60 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E _____________________._______—————-———— “+50 .-"h hail-armed three—1111mm muree gerver: the ['aille-ing JimLIH: anl 1: 2|} Mia at I13 ]1[' lugging anl 2: ll]I Mia at ISL? 11f leading anl 3: ll]I Jew at unit}; [31' anl :1: lb Mia at Dr:- ]1[' lugging The line mirage at the [mad i5 gee 'v' ([Tlﬁ :11 6|} H1. and the line impedance is QUE + jUﬂ4 ﬂ. Find the line Veilmgc and power i'uemr at ihe HULH'CC. SOLUTION: LoMi: 20 kVA a}: 0‘8 PIT/(623 LoadZ'. 10 |<VA aton PFX " Max:432 mm at PF W4". ibKVA Akave PP KM: 208V Am; VANl— i9} = '20 VM’M \IQN; izoLOo \lAvmr Problem 11.60 Chapter 11: Polyphase Circuits 2 Irwin, Basic Engineering Circuit Analysis, 9/E _____________________________————————————— .A ,’ ’ o slwﬁ = «2:14 Lax (Myem (36.87 mm ’ — 10k " . = 3. , . b (M 532M) , 75w (0*!) 33L45 57K Pr: J; til ‘§5\: __P_. .-: ___Q_K_ =. ‘OKVA I i ’ ; _L0_'g w" = 333 o KUA \$3|€¢ 5 L (I) L ’ 3 [6k 094-: 6 gq = 5.33 L55-I3 KVA‘ ,, e , ‘ 5’ 3' 5 Problem 11.60 Chapter 11: Polyphase Circuits Irwin, Basic Engineering Circuit Analysis, 9/E 3 PP , m (1.15% aaﬁ") PP= 0-112. _______________________.___———————————————— Chapter 11: Polyphase Circuits Problem 11.60 ...
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• Fall '10
• MicahStickel
• Electrical impedance, Basic Engineering Circuit, Engineering Circuit Analysis, Polyphase Circuits Irwin

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IRWIN 9e 11_60 - Irwin Basic Engineering Circuit Analysis...

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