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IRWIN 9e 11_70 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 11.10 Find F in the netwerk in Fig. Pl L't'l} fiLth that the total Matt has a power factor 01' 0.3? leading. + Balanced Balanced - - time-phase three phase lead entree 2t} lull-FA Mt]? p1 Figure F1130 SOLUTION: I 5L : $20 M 10M" (0- 707) ‘— sb: (,sao L45” MVA va‘b/g 89.5 KV/ims 5"“ a 3723i 145°: €2.67 445° MW) 5p,» = +72 +] 4.72 MW—l Quid == 4-72 W! Va? QSMW = “C04”, (0.23%): ’afirs'o Shem 3 514.3 L” 99‘5"" M UA’ Chapter 11: Polyphase Circuits Problem 11.70 2 , Irwin, Basic Engineering Circuit Analysis, 9/E Qmw = — 9x427 M Vafiy Qc= ’[Vab/lwc QC; ano' QOIOL : ' Q'GVM— 9'12H (sin ’13? M var/«L " 31"37M .—’— “(39-SP/f)b(377)c C: )6‘5fi/AF Problem 11.70 Chapter 11: Polyphase Circuits ...
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