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IRWIN 9e 11_73 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 11.13 Find IT in the nova-wk in Fig. Pl 1.7-‘3 an that the tum] JDUILI haa a DUWL‘I' factor 01' IIIH leading. + 4.6- Wrms Balanced Bala need _ _ three-pH ase three-p hase I load source ‘ 5 MW; 60 Hz 0.3 pf lagging Figure Pug; SOLUTION: -= 4'16k. V&m£ " 6M L004" (0‘8) (/3 u ’ 3 6135.870 MVA ’ _ 2M )s,,¢)_ VA , o D 5,95 : fay/09436.87; 2Ma94 36.8.7- P,_.¢= )‘é k 93.: m"(o.8): 35,570 3,,¢ = $2436.23?" Mm &I‘_¢= (‘2- MVQ’O’ (go/cl: Chapter 11: Polyphase Circuits Problem 11.73 2 Irwin, Basic Engineering Circuit Analysis. 9/E S = -’ swig" ” P’rb rm 5 __ u _ .m " " " 'WQMV \ he») PFNN 067 } 2 A QM, I #3 bung" MVA QM“ = - QC. = Qnm* Qo’oL =»7*15k— MAM QC: "'a/75— MVOVI QC: ‘1 Vale); N62 C: “1975’”! “(4.610; (377) C=~ 497%; AF ______________________.___________———————-—— Problem 11.73 Chapter 11: Polyphase Circuits ...
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