IRWIN 9e 3_43 - lrwin Basic Engineering Circuit Analysis...

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Unformatted text preview: lrwin, Basic Engineering Circuit Analysis, 9/E 1 3.43 Use nodal analysis to solve for I ,4 in the network in Fig. 18.43. Figure P343 SOLUTION: v. 3 :1 v5 KCL 4,6 Swine/LWOGLL’. i3+1,: 5’41“; 2 iii-r 14:11;— , 54 __\{2_+2 '— l L. E? S” 5V: " gVL + 7'5", ' 79 V1 2 300+ IZV3+l20 (~75 v, -—i2.-s'v2_ ~12V3 + 9/5 c420] " Chapter 3: Nodal and Loop Analysis Techniques Problem 3.43 2 Irwin. Basic Engineering Circuit Analysis, 9/E IA = 3 5 V«»v, ~ SOs/s) VQ'VIZVQ - —V,——v3+\/,,:o ) KCL kt MJEopemeLj IL+ §+ 1A :0 __\_{L.+ 5+ 32> ; O ‘1 5' 5V, 4 16‘0 4— avg ISVI + LIVB ; “WU—O ov,+ V; + avg f!” 4V4 ~§vsa; ,24, 794—1204 pizvg + 0V1, +7 5vS : Z0.0 :0 ’V, “i” 0 V; "V3 ‘i‘ V41 -r- 0v; ; O 0V, '4' V2 "’ V3 +’ OVA, 4* 0V: 2 ’8 5V, + 0V; +11%) 4— ové + 0V; : -/0'2) VI 5 $‘22V V2 :p"i 01 V V3 ¢ ’24. 03. V V‘i : —-2§.‘Zl V Vs”: "8‘05 V IA : Xi ': ’43:..0} ’5 5' IA : - 5‘3 A Problem 3.43 Chapter 3: Nodal and Loop Analysis Techniques ...
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