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lecture 4

lecture 4 - CHE 349 Lecture 4 CHE 349 Kinetics and Reactor...

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CHE 349: Kinetics and Reactor Design Lecture 4 Lecture 4 Jing Wu 350 Tiernan Department of Chemical Engineering ± [email protected] ² 973-642-7064 CHE 349 - Lecture 4 by Jing Wu 2 Assignments Week 2 Required Reading Lecture 3: Sec. 2.1 – Sec. 2.5, P129-P137. Lecture 4: P83-92 (before 3.3.4) Homework I Lecture 3: P2-3, P2-12 (if you haven’t finish) P2-8 Lecture 4: 3-6, 3-7 (a) Quiz I CHE 349 - Lecture 4 by Jing Wu 3 Design Equation Summary = A A A r C C v V 0 0 A A A r C C v V = = 0 0 τ () exit A A r X F V = 0 A A A r F F V = 0 CSTR A A r dV dX F = 0 A A r dV dF = A A r dV dC v = 0 PFR = dt dN V r A A 1 dt dC r A A = dt dX V N r A A 0 = Batch F or N C A X A Express r a in terms of C A , X A or F A V ÅÆ C A , X A or F A = = 0 0 A A C C A A r dC v V = = X A A r dX C v V 0 0 0 A A r X C v V = = 0 0 = 0 A A F F A A r dF V CHE 349 - Lecture 4 by Jing Wu 4 What do we need? V r dt dX N A A = 0 exit A A r X F V = 0 A A r dV dX F = 0 Design Equations in terms of conversion:

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lecture 4 - CHE 349 Lecture 4 CHE 349 Kinetics and Reactor...

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