SolutionsAMS 161 Final Exams

SolutionsAMS 161 Final Exams - Solutions to Past AMS 161...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Solutions to Past AMS 161 Final Exams AMS 161 Final Exam Solution for Spring 2010 1. a) (e^9/3 - 9^2/2)-(1/3), b) -cos(e^(3x^3))/9, c) 4x - 4ln(x+1), d) (5/3)sqrt(2x+2)(x- 2) (done by parts and simplified) 2. a) e^4x[x/4 - 1/16], b) (x^8/8)[ln(x) - 1/8], c) -x^2*cos(2x^2)/4+sin(2x^2)/8 3. a) -1/[2(x-2)^2] undefined at x=2, b) 1/7, c) -1/(x-1) undefined at x=1 4. LH < MP < TI < TP < RH 5. a) int from 1 to 3 of pi[(2/y^2)^2], b) int from -1 to +1 of pi[(6-x^3)^2 - (2-x)^2] 6. a) int from 20 to 80 of 50 + 5(80-x), b) int from 0 to 12 of 62.5pi(10-10h/12)^2*h, c) int from 0 to 250 of 62.5(250-y)4ln(y+1) 7. a) ln(2) + x/2 - x^2/8 + x^3/24, b) ln(2) + x^2 - x^4/2 + x^3/6, c) xln(2) + (1- ln(2)/6)x^3 + (-1/2 + 1/6 + ln(2)/120)^x^5 8. an = 5^n/n!, limit of 5/(n+1) -> 0, rad of covergence is unbounded 9. a) y = Ae^[-(2/3)e^(-3x)], where A = 5e^(2/3), b) 6e^t - e^(4t) 10. a) T = 70 + 60e^(kt) where k = (1/8)ln(1/2), b) y = 4000(1-e^(-t/20) AMS 161 Final Exam Solutions for Fall 2009 1.{6 pts each} a) e^8/4 - 25/4, b) (1/6)sin(e^(3x^2)), c) 2x + 6ln(x-3), d) (done by
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 2

SolutionsAMS 161 Final Exams - Solutions to Past AMS 161...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online