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Unformatted text preview: used are: Loop i 1 : v ab = L 1 d ( i 1-i 2 ) dt-M di 2 dt Loop i 2 : = L 2 di 2 dt-M d ( i 1-i 2 ) dt-" L 1 d ( i 1-i 2 ) dt-M di 2 dt # v ab = L 2 di 2 dt-M d ( i 1-i 2 ) dt By applying the same elimination procedure as before, the equivalent inductance can be de-termined: v ab = L 1 L 2-M 2 L 1 + L 2 + 2 M ! di 1 dt = L eq di 1 dt 2...
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This note was uploaded on 10/05/2010 for the course ECE 329 taught by Professor Kim during the Spring '08 term at University of Illinois, Urbana Champaign.
- Spring '08