CIS3360_HW4_solution-3-23-10 - CIS 3360 Security in...

Info icon This preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
CIS 3360 – Security in Computing Spring 2010 Homework 4 (100 points) Due on 02/21/2010, 11:55 PM NOTE: Homework submitting instructions: (i) Acceptable file formats: .doc, .docx or .pdf file (ii) The file name should be yourlastname_yourfirstname_HW4 (iii)Include your Full Name and your PID at the top of your document. 1) [10] Permute the input 1110 0100 1001 1011, if a permutation is defined as follows: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 14 10 6 2 16 12 8 4 13 9 5 1 15 11 7 3 Answer:
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
1 1 1 0 0 1 0 0 1 0 0 1 1 0 1 1 0 0 1 1 1 1 0 0 1 1 0 1 1 0 0 1 2) [10] Permute the input 1010 1100 1011 1101, if a permutation is defined as follows:
Image of page 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 4 2 3 1 8 6 7 5 12 10 11 9 16 14 15 13 Answer:
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
1 0 1 0 1 1 0 0 1 0 1 1 1 1 0 1 0 0 1 1 0 1 0 1 1 0 1 1 1 1 0 1 3) [10] Given the following permutation, find the Caesar cipher equation and the Caesar cipher alphabet that has been used.
Image of page 4
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
Image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
18 19 20 21 22 23 24 25 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 Answer: Caesar cipher equation is c = E( p ) = ( p + 18 ) mod (26). Caesar cipher alphabet along with plain alphabet is given below: 0 1 2 3 4 5 6 7 8 9 1 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 2 0 2 1 2 2 2 3 2 4 2 5 a b c d e f g h i j k l m n o p q r s t u v w
Image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern