Handout 2 - CIS 3360 Security in Computing Spring 2010...

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CIS 3360 Security in Computing Spring 2010 Handout # 2 – Network and IP addresses Prepared by: Shafaq Chaudhry and Ratan Guha How many bits in a byte, how many KB in a meg etc etc. This information has been put together by Techeez.com. I am providing this for your information. Old Standard bit b 0 or 1 byte B 8 bits kilobit kb 1000 bits Kilobyte (binary) KB 1024 bytes Kilobyte (decimal) KB 1000 bytes Megabit Mb 1000 kilobits Megabyte (binary) MB 1024 Kilobytes Megabyte (decimal) MB 1000 Kilobytes Gigabit Gb 1000 Megabits Gigabyte (binary) GB 1024 Megabytes Gigabyte (decimal) GB 1000 Megabytes Terabit Tb 1000 Gigabits Terabyte (binary) TB 1024 Gigabytes Terabyte (decimal) TB 1000 Gigabytes Petabit Pb 1000 Terabits Petabyte (binary) PB 1024 Terabytes Petabyte (decimal) PB 1000 Terabytes Exabit Eb 1000 Petabits Exabyte (binary) EB 1024 Petabytes Exabyte (decimal) EB 1000 Petabytes IEC Standard bit bit 0 or 1 byte B 8 bits kibibit Kibit 1024 bits kilobit kbit 1000 bits kibibyte (binary) KiB 1024 bytes kilobyte (decimal) kB 1000 bytes megabit Mbit 1000 kilobits mebibyte (binary) MiB 1024 kibibytes megabyte (decimal) MB 1000 kilobytes gigabit Gbit 1000 megabits gibibyte (binary) GiB 1024 mebibytes gigabyte (decimal) GB 1000 megabytes terabit Tbit 1000 gigabits tebibyte (binary) TiB 1024 gibibytes terabyte (decimal) TB 1000 gigabytes petabit Pbit 1000 terabits pebibyte (binary) PiB 1024 tebibytes petabyte (decimal) PB 1000 terabytes exabit Ebit 1000 petabits exbibyte (binary) EiB 1024 pebibytes exabyte (decimal) EB 1000 petabytes
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Example 1: If a link has a bandwidth of 1Mbps, how much time will it take to transmit 1000 bits of data by Alice, ignoring all delays except the transmission? Solution: Here, 1Mpbs = 1=10 6 bps = 1000000 bits per sec => 1000000 bits can reach from source to destination in 1 second => 1 bit can reach from source to destination in 1/1000000 sec = 10 -6 s = .000001 s = 1 micro sec = 1 μ s Therefore, 1000 bits can reach the destination in .000001 x 1000 s = .001 s = 10 -3 s = 1ms Alice Bob When Alice sends a packet to Bob, then the time it takes for the packet to reach from source to destination depends on: o Transmission time, which depends on the bandwidth o Processing time at the source o Propagation time from the source to the router o Queuing delay at the router o Processing time at the router o Propagation time from router to destination Router
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Example 2: If a link has a bandwidth of 1Mbps, how much time will it take to receive 1000 bits of data from Alice to Bob, ignoring all delays except the transmission? Here data is received by the router and then transmitted to Bob. Solution: Here, 1Mpbs = 1=10 6 bps = 1000000 bits per sec => 1000000 bits can reach from source to router in 1 second => 1 bit can reach from source to router in 1/1000000 sec = 10 -6 s = .000001 s = 1 micro sec = 1 μ s Therefore, 1000 bits can reach the router in .000001 x 1000 s = .001 s = 10 -3 s = 1ms Similarly, it will take 1ms to send the data from the router to Bob. So the total time to
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This note was uploaded on 10/05/2010 for the course CIS CIS 3360 taught by Professor Guha during the Spring '10 term at University of Central Florida.

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Handout 2 - CIS 3360 Security in Computing Spring 2010...

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