exam2s - Numerical Analysis/Exam #2/November 23, 2009...

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Unformatted text preview: Numerical Analysis/Exam #2/November 23, 2009 SOLUTIONS 10 a 35 = , y = 0.8 + 3.18x 30 b 103.4 1 2 2. (a) 2 1 6 3 2 1 + i i −1 + i (b) 0 , 1 , 0 −1 − i −i 1−i 1. (c) Arithmetic 3. (a) T= x0 = 0 , 0 0 −1 3 4 1 −4 , 0 3 4 4 10 c= 0 9 4 3 , , x3 = 25 3. 3 16 x1 = 3 , x2 = 3 , 5 (b) A = 5, A−1 = 3 , so the condition number is Yes. 4. (a) b2 = 1, all other coefficients are 0. (b) Since f is odd, there are only sin terms. bk = = = 1 π 1 π π x sin kx dx −π − x cos kx k π π π + −π −π cos kx dx k 1 x cos kx − π k −π 1 2π cos kπ = − π k 2 k = − (−1) k ...
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This note was uploaded on 10/10/2010 for the course MATH 01:640:111 taught by Professor Carey during the Spring '10 term at Saint Louis.

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