This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: of this survey. Suppose N persons were selected for the survey and n of them answered YES . Also, let us assume that the fraction of people who cheat on their taxes is p . Also, let us deﬁne events A and B as A ← Event that Answer = YES B ← Event that the Toss = Heads Now, P ( A ) = P ( A ∩ B ) + P ( A ∩ B c ) (1) = P ( B ) · P ( A  B ) + P ( B c ) · P ( A  B ) (2) = 1 2 · 1 + 1 2 · p (3) = p + 1 2 (4) Therefore, p +1 2 = n N which implies p = 2 nN N . 1 Note that 2 n > N because at least half of the people will answer YES as half of the people will get a Heads as their coin toss. Therefore, you have estimated the fraction p of people who cheat on their taxes using this survey. 2...
View
Full
Document
This note was uploaded on 10/05/2010 for the course BUS 1142 taught by Professor Miller during the Fall '10 term at Carnegie Mellon.
 Fall '10
 miller
 Taxes

Click to edit the document details