CE 223 Assignment 2 - Haley Orr 28 October 2009 CE 223 Jia...

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Haley Orr 28 October 2009 CE 223 Jia Homework Assignment #2 Chapter 9 #3 Chapter 12 #1, 5, 6, 11, 12 Chapter 9 #3 Link Interchange 1-112 113-2 117- 111 111- 110 110-109 109- 108 108- 107 116- 102 102- 103 103-104 104-105 103-114 1-2 1,000 1,000 1,000 1-3 5,000 5,000 5,000 1-4 3,000 3,000 2-1 4,000 4,000 4,000 2-3 3,000 3,000 2-4 4,000 4,000 4,000 3-1 5,000 5,000 5,000 3-2 6,000 6,000 3-4 1,000 1,000 1,000 4-1 2,000 2,000 4-2 1,000 1,000 1,000 4-3 3,000 3,000 3,000 Total 20,000 19,00 0 20,00 0 4,000 23,00 0 14,000 Chapter 12 #1 Given: Δ = 23°42’ right = 23.7° D = 1°45’ = 1.75° PI = 27+85.50 Determine: Tangent Distance Curve Length Station of PT Solution: sin ½D=50/R R=50/(sin ½D) = 50/(sin ½(1.75°)) = 3274 ft Tangent Distance T = R tan ½Δ = 3274 tan ½ (23.7°) = 686.9 ft
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PC Station = PI Station – T = 27+85.50 – 686.9 = 20+98.60 Curve Length L = 2πRΔ/360° = 2π(3274 ft)(23.7°)/360° = 1354.3 ft PT Station = PC Station + L = 20+98.60 + 1354.3 = 34+52.90 Chapter 12 #5 Given: G
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CE 223 Assignment 2 - Haley Orr 28 October 2009 CE 223 Jia...

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