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Solutions5 - BC368 Biochemistry of the Cell II Problem Set...

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BC368 – Biochemistry of the Cell II Problem Set #5 – Carbohydrate Catabolism ANSWERS 1. See the paper cited for a detailed explanation. In brief: If hexokinase is not inhibited, then the two ATP-requiring steps at the beginning of glycolysis will deplete ATP stores because the preparatory phase of glycolysis operates at a faster rate than the payoff phase. ATP is used faster than it is regenerated, and the yeast die. 2. a) The absence of TPI would mean that half of the carbon skeleton of glucose would lead to a dead- end product. Dihydroxyacetone phosphate could not be converted to glyceraldehyde 3-phophate and proceed through the “payoff” phase of glycolysis. This would cut the net yield of ATP from 2 to zero. In addition the aldolase reaction would also back up because of a build-up of DHAP. b) With TPI present, dihydroxyacetone phosphate will be converted to glyceraldehyde 3-phophate and so the net yield of ATP from anaerobic glycolysis would be restored. Having only 10% TPI
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This note was uploaded on 10/12/2010 for the course BC BC367 taught by Professor Millard during the Spring '10 term at Colby.

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Solutions5 - BC368 Biochemistry of the Cell II Problem Set...

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