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hwk_15 - 2244:: m 4t Two children are standing on a diving...

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Unformatted text preview: 2244:: m 4t Two children are standing on a diving board that weighs 146 113, f Knowing that the weights of the children at C and D are 63 21) and 90 1b, rah % spectively, determine (a) the reaction at A, (b) the reaction at B. : {PM - 5) (mm) as; _;.<:4a1;.ar 3’ 1 E AK , - V. . .b r . ; I 1"” ‘ #quawsmj 57: PM: #fiPuiLfizMsea 3 5 gzfig‘ I We: MMDT iéNORE Ax 3:51 W: :1 i4 m9 Km @2ch 7 - =5 =0 - ‘ REM?" mo’ A :3 r’mm‘ BE .How .: fa O AX ' fiflgfig kJoflgfiffl-LELR (LURREIWF view Sflvflfidfig 2mg may EFFIUETN‘T’ EMS => intle MI 1%“ t: i ——-=o Inga-Wong; 2:5 Tms' WET {-712 EJ—(WW’ETES 'RQQC/TLOAB @ A mi am. my . fr ’ _ $8?” ,, - I fife-4 8,621 - @2me (($31 1*)- WWafi-(zmsjéfi ., . " 735' “43082 W Rana, gold AY (NOTE 795 @kW TH€ ‘FW 0‘? 2‘2" yzoe :T15‘__j__m- DI’TOIJH'L EQUIL; _ V EN; I’1" ‘5 M ALjEEMfiIE “ " a w,Ms_;s _ ‘ -,‘ - £ ' 924’ i m 2mg. : male/Aja- ngbfi— @Wj—aww _ -' 20,125? - 455% g 97mg rag-{3+ “21l»l+670.l-14éw63~% so. 6’10» t, :53 3/ 1 j: Sax-=0 55’ SHEEth 22-132 $00 QHEETS JIM 200 SHEETS \ 2246‘ x; .K .r 1 ‘ Awfl'U—‘an ‘ ‘m w” 2.2 1.3 ft The boom on a 9500-1?) truck is use<i to unload a pallet of shingles of weight 3500 lb. Determine the reaction at each of the two (a) rear Wheeis B, (E9) front Wheels C. — _' 1 if .9- 55K 3 I 4' In - (9‘9" :20 M w 490 J E 19324“ "44935 316%: max-at; ML . 2337a; 5* EEK I 95K 05')" 2'57 (1590+ W :0 ’ who": ‘5‘?” Bae’BY-a 91.27 K {f By: 2.7K 5.4K jfi‘ $360 735K+§fi9v951<+2©e©e€> ! __wi%+'3’__"0 */ " @TIR€@‘E=Z;1K I I f fiRE@ :. 3:5K Z—‘WC’ Mb , 5. W’GEH- w 553' E118 3'4.“ . I f 4.} l 3 75) N p 75 N f E For the beam and loading shown, determine the range of values of the distance a for which the reaction at B does not exceed 250 N down- 7 ward or 500 N upward. aw flats: 2450M @ng WS‘T'EEM wagng 1:5: WWW-T 3': i ME eymzfle 500M mew (MET MM 416%! FAT E MD some fibre an! H WW 75°”. 75w fl! { 12§N_ on] m 0.05,,“ 0.15),“ § ZMAeo ——“: 55> gr + {xi-Dy ~—e.r6@5) ——7S*0(ée7é@ + as {65019 «:0 . g ' ~ 753mm“)? [3.76 $554553. H50; 35:9 ' « TIMm-fimbj of- 75 2:40 _ ' ifi :0 F754: #7522 —IZ$”+5'€3<:>+ (>5 :0 DJ 5 Her a: o,:¢:as:)+75 _ ‘ 15w a 3" 9.251111. 03 [ZS/mm WW? MW jjfwe fim/ [GE AT “E? QXCEEb/kaéf 25014! glgiéfiir 1%; gm? VALUE AT E WHE" ’5‘" » 1W (MAM - n. 7} MI E . E l f}. Lyn avg 6.5% . m i E EMMPO Ire «My 4—Way -7sa .cm._o,. 2:50» =9 _ 22' ’3‘ egazmpgé reggae? “.3375 a 45mm #450 :43 25< rd y f «aéizamwnlz 5 :62? «‘73? W3 42yu-7529450 ==o g; j s [.375 N 5": WWW)" £50 flew : arazs’m me 25mm U) l— m LL; r?) f} SHEETS 7-7:?!) Si-iEETS AEP , e zen 1.2 kN 1.5m _ is L12 m"|0.8 HILLS m For the given loading of the beam AB, determine the tange of values of the mass of the. crate for which the system will be in equilibrium knmving that the maximum allowable value of the reactions at each 311 art is 2.5 kN and that the reaction at E must be directed downward. mas ‘ewf as tiliYiAdD B623 ACT rwdDe-‘fire I in;th same/fee puffty'w r30 WWW WITH TH'E cam—Y {W (wt—E AT "e me My 9}»??ch 0'4"].1-P6 eon-f. night WM 6] (E W Air/43 :7; e) 439m: 5 ammo» 2 57%, £2.5an _ We (9,94,, Mm 2.2% 3 m 67: 0 ’16 ea eweng (“1.6. fig: my m com/MT w/m WWW E) 1 EMA‘O '"':Llfia§(m,79- thaeua-ivgfizm.swig—r21. L70. -' ' . W ‘13mm3fi is; a? 78a8€j ngfimBM? WK mfiog @ A 3 i=0 Afl—m—Le +0379 :0 . 1 - ‘7 ' ~ “ gem Ey=25>§1~14 mu, A7 67sz, WET 2.52434 RECQFWE whio H.414" 3;Z*2.5i1‘3m>+5]’g%5 fl”: lfigj‘w‘ r area Mamt-zghefi—f—a ,ayzvemf >25€le if; £191 OK Lg ~12513¥l rm: “g 17M EY<25£A cw“; _€z»>“m.F-.Q»_ ZMgo - +g.7.(§:_a:m)+[tcg(mm) + 2;; E :0 2'95 ., *25»;.2*l.tw-E)r+i59‘=9 air/395452ng 63K v’t/ '78 waééxezt ‘ 2,215 = 35-h! fl 6 L59 é»! egg? ...
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hwk_15 - 2244:: m 4t Two children are standing on a diving...

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