hwk_32 - Determine by direct integration the moment 0f in...

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Unformatted text preview: Determine by direct integration the moment 0f in- erfia of the shaded area with respect to the y axis. WI 91;! .c we 7 «5-4» fiy‘anptgfmxiT “RULE” we? use Vflfiaq’efaf 6% “K" 144(ng (if: atlas, £3 (M) wee/t it K= (w; (W Y.“ Mi? MD Msgflgeflxafibamétjou 459% exec/T («a a? w a." 3‘7 . 6 a . 6;; . if: gflb-bé’éfldx “5"” $19):- bQ‘fi) 01.x l\ 6...... CI ms: 2.? _. 39/? $13, a. 5 air __ sz‘z] 22-141 50 SHEETS 10E! SHEETS 22-144 200 SHEETS 22-142 333%" AMnm-J E 9 4 Determine by direct integration the moment of I 3 ID inertia of the shaded area with respect to the y axis. - IY - 035?? (693 9. 8 Determine by direct integration the moment of 3.0 ‘1, lg £1 inertia of the shaded area with respect to the x axis. 17‘: EFF ( ) mementos,» H» “K“ “<2“ M TEENS a; magmas; (2070) 3:? QT‘KCZUKB4'C, (0,5) ‘5'? If): K(0)1+Q_ e '0 = K («E-— Lee, we CAM WWW y fizéiéz-X) 949 15::me WHERE am you: [£44aax2)]£x ”:x’flgfl’fli; “‘3’ : OK E )M—X a 4;. bx‘fefizd gift?! f??? em}: “ gait, 22-141 50 SHEETS 22—142 109 SHEETS 22—144 200 SHEETS @ AMF'nI'J $6; MET-Hop” M5 %8 =9 ix :jdix usmeinaacL —_-(260 <9 105 24% 372%! _MSETOM5 WW3! ._ mm 3% Determine the moment of inertia and the radius of gy-rafion of the shaded area shown with respect to the x axis. J—T Determine the Rolar moment of inertia and the Eolar radius of ' _ J 2% gflation of the shaded area shown with resEect to Eoint P. J .. J ' /‘p\x\"\Ji fioicimma N255 use JF:.FJ:XTJ:Y a—A We MY M6 NTaewfg @ T’OFNT: (a) Determine by direct integration the polar moment of inertia of the area shown with respect to point 0. (b) Using the result of part a, de- termine the moments of inertia of the given area with respect to the x and 50 SHEETS 22-142 100 SHEETS 22-144 200 SHEETS y axes. 22-141 nMFAn €13}th ...
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