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hwk_39 - fififiei ngLWAE MMWMWM 65:26 16138 A 120ekg...

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Unformatted text preview: fififiei _.. ngLWAE MMWMWM 65:26 16138 A 120ekg block is supported by a rope which is wrappeci 1% times around a horizontal rod. Knowing that the coefficient of static friction Ee- tween the rope and file roé is M determine the range of values of P for which equilibrium is maintained. .. déjdrsnfirfim 1% 3 L07 In the pivoted motor mount shown, the weight W of the 175-lb motor is used to maintain tension in the drive belt. Knowing that the coef- ficient of static {fiction between the flat behind drums A and B i_sjl._f_lfl and neglecting the weight of platform CD, determine the largest eouBle which can be transmitted to drum B when the drive ghjum A is rotating clockwise. CE 24532-, _ $11411 811% Biocks A and C are connected by a rope that passes over churn B. Knowing that the drum rotates slowlv clockwise and that the coefficients of friction at all surfaces are ,us — 0. 30 3115: ,qu — 0 20, determine the smallest mass of block C for which block A (a ) wifl remain at rest (In) Wfll be in km pending motion up the incline, (c ) will move up the incline at a constant speed. .. mane ’ meme? 11111 e11: 1511016116,: 1* “12.14211 ”17131111111 #11. I I Ce” 11111 1— 1;: @1531;ng i? “@1ng i=1 ”1111F hESFf 1111131111111 ‘3 1 W1 . "13‘1" '16?) UUWE‘K 11¢£M1~1§1 a“: 1,165 115% 251-3??? $151?1e, mam—bf Nani-151, . \ 12312 $15?) 1,1317% $1111.11 3.811143 \‘éffix‘g’ QUE 111191113“: “811} 391.135.. ' ' {S}. We 12:; 1:111 111111111) flame” ee111$11 $1:ng 111,111,517,“ 11151;; 31: ‘11 £11311 1.; 1111;613:1111 111.27% 111%? 111111111: 1.11 1131:1115 W113 . 1111) each weflwfieae . . 1 I 1 1 1 3 i i I | I i I I i i E i i 32 x, ‘55:? @1153 2%??? 23;? mmmqr MSOJ a" K a; «£3 ~...r'.‘: Mi}; «‘I‘u’ 93 fivifii i if was ‘ f \ Elf’fipfiuflzfv’é; W ”5%? 4!.,AflgfifigwmwmmWM.“ ... ..... L ;;_____.,___;.__=_£m_;:,5 ;., ”Wm nmmmmm‘ @1343“ 3 417%? 3L3: 23333335 3333335 3757;55:373de 5% E , Ixfia? >3?! ”/33 ‘ ““3 3 .3 4.3.“: 235;; “xii 33”“; 5-3-3315: 33-39% 53 £35 233:3;ng :33; £333 3: , x , 33 335332 3-3333? LL WHEY (3333:3333) 7333:3333; <3 5.333;. g ” w W§W j MT 35363 TLFE‘L 8:3,, {3331; fig: 33L”? ELM {:3 35' LL33: way 3:533: fl}: 33,333;- 3% ...
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