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# EX2 - Version 049 ex2 Keto(58610 This print-out should have...

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Version 049 – ex2 – Keto – (58610) 2 = + k bracketleftbigg 2 Q r bracketrightbigg , so V 3 R = k bracketleftbigg 2 Q 3 R bracketrightbigg = k Q bracketleftbigg 4 6 R bracketrightbigg = 4 k Q 6 R , and for 2 R < r < 3 R , V r = V 3 R = V 2 R { inside a conductor } V 2 R = 4 k Q 6 R , and for R < r < 2 R , V r = k bracketleftbigg (+ Q ) r + ( - Q ) 2 R + (+2 Q ) 3 R bracketrightbigg = k Q bracketleftbigg 1 r + ( - 3) + (4) 6 R bracketrightbigg = k Q bracketleftbigg 1 r + (1) 6 R bracketrightbigg , V R = k Q bracketleftbigg 1 R + (1) 6 R bracketrightbigg = k Q bracketleftbigg (6) + (1) 6 R bracketrightbigg = 7 k Q 6 R , and for 0 < r < R , V r = V R = V 0 { inside a conductor } V 0 = 7 k Q 6 R . The potential within a conductor is con- stant and the electric field within a conductor is zero. 002 10.0 points Consider two concentric spherical conducting shells. The inner shell has radius a and charge q 1 on it, while the outer shell has radius 3 a and charge q 2 on it.
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EX2 - Version 049 ex2 Keto(58610 This print-out should have...

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