BB lecture 9-10 carbon cpds

# BB lecture 9-10 carbon cpds - Solutions consist of a solute...

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Solutions – consist of a solute dissolved in a solvent. In living cells, the solvent is water. Solutions may be expressed in different ways – two examples: Percent Molarity A 5% glucose solution contains 5 g of glucose in how many milliliters (ml) of solution? Another method of expression is in terms of molarity , or moles of solute per liter soln. A mole of a compound (cpd.) is the number of grams of that cpd. equal to its Mol. Wt. (aka formula wt., ‘FW’) Example: What is the mol. wt. of glucose [C 6 H 12 O 6 ]? at. masses are C = 12, H = 1, O = 16 A 1-molar (1 M) solution of glucose contains ___ g glucose (1 mole) dissolved in enough water to make 1 liter of solution.

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How much glucose would be needed to make 100 ml of a 0.1M solution? [MW (aka FW) of glucose = 180 g] Answer: It would take 18 g in a liter to make a 0.1M solution. But, a volume of 100 ml would only require 1/10 th of 18, or 1.8 g.
If molarity means moles of solute per liter of solution, what is osmolarity ? Osmolarity is a method of expressing solution concentration based on the number of particles in solution. OSMOLARITY = MOLARITY x NUMBER OF PARTICLES MOLECULE Osmolarity is expressed in the units osmols , (or osmol .)

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Consider these rx: NaCl -------- Na + + Cl - 1 molecule 2 particles Glucose ------ glucose 1 molecule 1 particle K 2 SO 4 ------- 2K + + SO
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