hw6_solution

# hw6_solution - EE321 Spring 2009 HW#6 Problem 24 ra:= 8...

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EE321 Spring 2009, HW #6 Problem 24 r a 8 = k v 0.01 = K 5 10 6 - = v a 6 = k v v a k v ω r - ( 29 r a K ω r = Set Te = Tl ω r k v v a k v 2 K r a + = ω r 428.571 = rad/s Problem 25 r a 10 = R f 50 = L AF 0.5 = V a 25 = V f 25 = Part 1 - Stall Torque i f V f R f = i f 0.5 = i a V a r a = i a 2.5 = T e_stall L AF i a i f =

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T e_stall 0.625 = Part 2 - No load speed i a 0 = V a ω r L AF i f - 0 = ω r_no_load V a L AF i f = ω r_no_load 100 = Part 3 - Steady-State Speed K 3.75 10 3 - = L AF i f V a ω r L AF i f - ( 29 r a K ω r = ω r L AF i f V a L AF 2 i f 2 K r a + = ω r 62.5 = Problem 26 Parameters: r a 0.3 = k v 0.1 = v a 25 = Variables of interest: i a ω r ( 29 v a k v ω r - r a = T e ω r ( 29 k v i a ω r ( 29 = T L ω r ( 29 2 ω r 400 3 =
ω r 400 = Given T e 0.2 ( ) 8.327 = T e ω r ( 29 T L ω r ( 29 = T L 100 ( ) 0.031 = ω ractual Find ω r ( 29 = ω ractual 237.449

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## This note was uploaded on 10/07/2010 for the course ECE 321 taught by Professor Staff during the Spring '08 term at Purdue.

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hw6_solution - EE321 Spring 2009 HW#6 Problem 24 ra:= 8...

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