{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hw8_solution

# hw8_solution - EE321 Spring 2008 HW#9 Problem 34 Note I...

This preview shows pages 1–4. Sign up to view the full content.

EE321 Spring 2008 HW#9 Problem 34 Note: I have adjusted array indices to start as 1 in this sheet N as 0 4 4 0 4 - 4 - 0 4 4 0 4 - 4 - ( ) T = N bs 4 - 4 - 0 4 4 0 4 - 4 - 0 4 4 0 ( ) T = N cs 4 0 4 - 4 - 0 4 4 0 4 - 4 - 0 4 ( ) T = By inspection N sslt 12 = P 4 = Now we have W as 1 1 2 1 N sslt P i N as i = = W as 1 4 =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Next R 2 N sslt .. = W as R W as R 1 - N as R 1 - - = W as T 1 2 3 4 5 6 7 8 9 10 1 4 4 0 -4 -4 0 4 4 0 ... = j 1 N sslt .. = 5 10 4 - 2 - 0 2 4 W as j j
i 1 N sslt .. = N T i N as i N bs i + N cs i + = N T T 1 2 3 4 5 6 7 8 9 10 11 12 1 8 8 8 8 8 8 8 8 8 8 8 8 = By inspection of the conductor numbers, the total number of conductors in each slot is 8. It is the Problem 35 n br ϕ r ( 29 262 cos 8 ϕ r 2 π 3 - = By inspection P 16 = Recall w br ϕ r ( 29 1 2 0 2 π P ϕ r n br ϕ r ( 29 d 0 ϕ r ϕ r n br ϕ r ( 29 d - =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
s'=c c'=-s Thus w br 1 2 0 2 π P ϕ r 262 cos 8 ϕ r 2 π 3 -
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 4

hw8_solution - EE321 Spring 2008 HW#9 Problem 34 Note I...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online