Disease - . 001 (2) P (P | NH) = 0 . 001 (3) P (N | NH) = 0...

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ECE 302, Diagnosing a rare disease Question 1: Consider a rare but deadly cancer. Statistically, 1 out of 100000 people will have this cancer. We have a powerful diagnosis test and the corresponding “conditional probabilities” are as follows. (We use P/N to denote positive/negative and H/NH to denote a person has or does not have this cancer. P (P | H) = 0 . 999 (1) P (N | H) = 0
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Unformatted text preview: . 001 (2) P (P | NH) = 0 . 001 (3) P (N | NH) = 0 . 999 (4) A family member of mine recently takes the test and the result is positive. Which one of the following method would you suggest? Why 1. Start a costly chemotherapy immediately. 2. Ignore the result, since all your other family members do not have that disease. 3. Take other types of tests....
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This note was uploaded on 10/07/2010 for the course ECE 302 taught by Professor Gelfand during the Spring '08 term at Purdue University-West Lafayette.

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