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36.
Use the Standard Normal Table to find the following probability for X = Student Heights for which the mean is 66 inches and the standard deviation is 2 inches: P(X > 69)
© A) 0.9332
© B)  0.0668
Go to Calc > Probability Distributions > Normal. Select "Cumulative Probability"
and
enter
<§>
C) 0.0668
66 for the Mean and 2 for the Standard Deviation. Select "Input Constant" and
© D) 0.8531
enter 69. Click OK and the answer Is 0.933193. This Is the probability that a height is
© E) 0.1469
les s
tha n 69 a
Tn e
Probability
that a
height Is
greater than 69
= 1  0.933193 =
0.0668
©F)0.1469
Alternate Method
zscore = (observed  mean)/SD = (69  66) / 2 = 1.5 = .9332 (found via Standard Normal Table)
1  .9332 = 0.0668
35.
Use the Standard Normal Table to find the following probability for X = Student Heights for which the mean is 66 inches and the standard deviation is 2 inches: P(66 < X < 69)
9
A)  0.4332
G o
t 0 Ca

C
>
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 Fall '08
 BARROSO,JOAOR
 Statistics, Probability, Standard Deviation

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