sol_hw_04

# sol_hw_04 - Solutions Probability Distributions 6.3 Boston...

This preview shows pages 1–2. Sign up to view the full content.

Solutions - Probability Distributions 6.3 Boston Red Sox hitting : a) The probabilities give a legitimate probability distribution because each one is between 0 and 1 and the sum of all of them is 1. b) = 0P(0) + 1P(1) + 2P(2) + 3P(3) + 4P(4) = 0(0.718) + 1(0.174) + 2(0.065) + 3(0.004) + 4(0.039) =0.472 c) The mean represents a long term average number of bases for each time at bat. and therefore does not necessarily have to be a whole number 6.5 Bilingual Canadians?: a) Their corresponding probabilities are not the same; that is, each x value (0, 1, and 2) does not carry the same weight. b) =0(0.02) + 1(0.81) + 2(0.17) = 1.15 6.15 Tail probability in graph : The observation would fall 0.67 standard deviations above the mean, and thus, would have a z -score of 0.67. Looking up this z -score in Table A, we see that this corresponds to a cumulative probability of 0.749. If we subtract this from 1.0, we see that the probability that an observation falls above this point (in the shaded region) is 0.251. 6.18 z -score for given probability in tails : a) First we calculate the cumulative probability for the total probability of 0.02 in the tails. We divide 0.02 by two to determine the probability in each tail, 0.01. Then

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern