265AHW4Winter10

265AHW4Winter10 - ECE 265A Homework #4 Due Friday March 12,...

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ECE 265A Homework #4 Due Friday March 12, 2010 In-Class. No late homeworks accepted. 1) 10 pts. The simple mixer below has been discussed in class. a. Derive the conversion gain of the mixer. (8) b. How do you bias the transistor to maximize the conversion gain? (2) Figure 1. Single Transistor Mixer 2) 25 pts: Image Rejection Ratio: Image rejection is one of the most critical functions of a radio (selectivity). Understanding why image rejection is hard to achieve will benefit you later. A. Given a phase mismatch, , from quadrature, derive an expression for the image rejection ratio. To achieve 60dB of IRR, what is the maximum phase offset? (15) B. Given a gain mismatch, , between the two mixing paths, derive an expression for the image rejection ratio. To achieve 60dB of IRR, what is the maximum gain mismatch? (10) Figure 2. Gain and phase mismatch in image rejection receivers.
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3) 60 pts: Crystal set: The circuit in the figure below is probably the simplest possible radio receiver. It is called a crystal set and is interesting because it
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This note was uploaded on 10/09/2010 for the course ECE 230 at UCSD.

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265AHW4Winter10 - ECE 265A Homework #4 Due Friday March 12,...

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