330_03_hw

330_03_hw - 3.01 Atomic Mass and 3.02 Avogadro's Number and...

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3.01 Atomic Mass and 3.02 Avogadro's Number and Molar Mass 3.05 Isotope amu % contribution 34.97 75.53 26.41 36.96 24.47 9.04 ave atomic mass: 35.45 amu 3.06 Isotope amu % contribution 6.02 x 7.0160 100-x ave atomic mass: 6.94 amu (6.0151x) + ( 1-x * 7.0160 ) = 6.94 6.0151x + 7.0160 - 7.0160x = 6.94 -1.0009 x + 7.0160 = 6.94 -1.0009 x = -0.08 x = 0.0749 7.49 1-x = 0.9251 92.51 CHECK: Isotope amu % contribution 6.02 7.49 0.4510 7.0160 92.51 6.4900 ave atomic mass: 6.941 amu 3.12 The thickness of a piece of paper is 0.0036 in. Suppose a certain book has an Avogadro's number (a) book thickness: 6.02E+23 pages 0 in 2.54 cm 1 pages 1 in (b) light years: 5.50E+21 cm 1 m 1 s 100 cm 3.00E+08 m 3.14 6.00E+09 atoms 1 mol 9.97E-15 mol 1 6.02E+23 atoms 3.16 How many grams of gold (Au) atoms are there in 15.3 moles of Au? 15.3 mol 197.0 g 3.01E+03 g 1 1 mol 3.18 What is the mass in grams of a single atom of each of the following elements: (a) As 1 atom As 1.0 mol As 74.92 g 1.24E-22 1 6.02E+23 atom As 1 mol As (b) Ni 1 atom Ni 1.0 mol Ni 58.69 g 9.75E-23 1 6.02E+23 atom Ni 1 mol Ni 3.20 How many atoms are present in 3.14 g of copper (Cu) 3.14 g Cu 1 mol Cu 6.02E+23 atoms Cu 2.97E+22 atoms Cu 35 17 Cl 37 17 Cl 6 3 Li 7 3 Li 6 3 Li 7 3 Li How many moles of cobalt (Co) atoms are there in 6.00 x 10 9 (6 billion) atoms?
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1 63.55 g Cu 1 mol Cu 3.22 Determine mass of each and compare. Pb: 2 atoms Pb 1 mol Pb 207.2 g Pb 6.88E-22 1 6.02E+23 atoms Pb 1 mol Pb He 5.1E-23 mol He 4 g He 2.04E-22 1 1 mol He 3.24 Calculate the molar mass of the following substances: (a) Li: 2 * 7.94 = 15.88 C: 1 * 12.01 = 12.01 O: 3 * 16.00 = 48.00 75.89 Which of the following has a greater mass: 2 atoms of lead or 5.1 x 10 - 23 mole of helium? Li 2 CO 3
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r of pages; calculate the thick 5.50E+21 cm 1 min 1 hr 1 day 1 yr 5.8E+03 yr 60 s 60 min 24 hr 365 day g g
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g Pb g He g/mol
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3.03 Molecular Mass 3.23 3.24 Calculate the molar mass of the following substances: (a) Li: 2 * 6.94 = 13.88 C: 1 * 12.01 = 12.01 O: 3 * 16.00 = 48.00 73.89 g/mol (c) C: 1 * 12.01 = 12.01 H: 1 * 1.01 = 1.01 Cl: 3 * 35.45 = 106.35 119.37 g/mol (e) K: 1 * 39.1 = 39.1 N: 1 * 14.01 = 14.01 O: 3 * 16.00 = 48.00 101.11 g/mol
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This note was uploaded on 10/11/2010 for the course CHE 201 taught by Professor Li during the Fall '10 term at Acadia.

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330_03_hw - 3.01 Atomic Mass and 3.02 Avogadro's Number and...

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