CH14LEC3 - 00,0 ,0 ,0 ,0 = 10--,---,---,---,-Y 2 X 2 X 1 =...

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Lecture: Chapter 14, Fundamental Mode Circuit Design Example 2 Determine the primitive flow table of a fundamental mode sequential circuit with two inputs X 2 and X 1 . The single output Z is to be 1 only when X 2 X 1 = 11 . Provided that this is the third of a sequence of input combinations 00 10 11 . Otherwise, the output is to be 0. Include a tabulation of outputs assuming that no spurious 1 output will occur during transitions between two states with 0 outputs. Both inputs will not change simultaneously. Step 1:
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Step 2: X 2 X 1
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0 0 0 1 1 1 1 0
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X 2 X 1
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0 0 0 1 1 1 1 0 ,0 6, 0 -, - 2, 0 1, 0 -, - 3, - ,0
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Step 3: X 2 X 1
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0 0 0 1 1 1 1 0 ,0 6, 0 -, - 2, 0 1, 0 -, - 3, - ,0 2 4 2 4 2 4 3 5 X 2 4
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Step 4: (56) (456) (456) (456) (456)(12)(16) X 2 X 1 0 0 0 1 1 1 10 12 = A 3 = B
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456 = C Step 5: X 2 X 1 00 01 11 10 12 = ,0 C,0 B,- ,0 3 = -,- C,- ,1 C,- 456 = A,0 ,0 ,0 ,0
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Step 6: X 2 X 1 Y 2 Y 1 00 01 11 10 = 00 ,0 11,0 01,- ,0 = 01 --,- 11,- ,1 11,- = 11 00,0 ,0 ,0 ,0 = 10 --,- --,- --,- --,-
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Step 7: X 2 X 1 Y 2 Y 1 00 01 11 10 = 00 ,0 11,0 01,- ,0 = 01 --,- 11,- ,1 11,- = 11 00,0 ,0 ,0 ,0 = 10 --,- --,- --,- --,- Z X 2 X 1 = 00 X 2 X 1 = 01 X 2 X 1 = 11 X 2 X 1 = 10 Y 2 Y 1 = 00 0 0 X 0 Y 2 Y 1 = 01 X X 1 X Y 2 Y 1 = 11 0 0 0 0 Y 2 Y 1 = 10 X X X X Z = Y 2 b Y 1
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X 2 X 1 Y 2 Y 1 00 01 11 10 = 00 ,0 11,0 01,- ,0 = 01 --,- 11,- ,1 11,- = 11
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Unformatted text preview: 00,0 ,0 ,0 ,0 = 10--,---,---,---,-Y 2 X 2 X 1 = 00 X 2 X 1 = 01 X 2 X 1 = 11 X 2 X 1 = 10 Y 2 Y 1 = 00 1 Y 2 Y 1 = 01 X 1 1 Y 2 Y 1 = 11 1 1 1 Y 2 Y 1 = 10 X X X X Y 2 = X 2 b X 1 + X 2 Y 2 + X 2 X 1 b Y 1 + X 1 Y 2 X 2 X 1 Y 2 Y 1 00 01 11 10 = 00 ,0 11,0 01,-,0 = 01--,-11,-,1 11,-= 11 00,0 ,0 ,0 ,0 = 10--,---,---,---,-Y 1 X 2 X 1 = 00 X 2 X 1 = 01 X 2 X 1 = 11 X 2 X 1 = 10 Y 2 Y 1 = 00 1 1 Y 2 Y 1 = 01 X 1 1 1 Y 2 Y 1 = 11 1 1 1 Y 2 Y 1 = 10 X X X X Y 1 = X 1 + X 2 Y 1 X 2 X 1 Y 2 Y 1 00 01 11 10 = 00 ,0 11,0 01, ,0 = 01 , 1 11, 1 ,1 11, 1 = 11 00,0 ,0 ,0 ,0 = 10 , 1 1 , 1 1 , 1 , X 2 X 1 Y 2 Y 1 00 01 11 10 = 00 ,0 11,0 01, ,0 = 01 , 1 11, 1 ,1 11, 1 = 11 00,0 ,0 ,0 ,0 = 10 , 1 1 , 1 1 , ,...
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This note was uploaded on 10/12/2010 for the course CSE 471 at Pennsylvania State University, University Park.

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CH14LEC3 - 00,0 ,0 ,0 ,0 = 10--,---,---,---,-Y 2 X 2 X 1 =...

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