# Lecture_16 - Solve for the Voltage Gain K n = 1 mA/V 2 V TN = 0.8 V Î = 0 V âˆ’1 EE 310 Lecture 16 Lecture 16 Page 4 The Common-Drain

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Sketch a Model for this Circuit EE 310 Lecture 16 Lecture 16 Page 1

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Example 4.5 EE 310 Lecture 16 Now solve for the voltage gain: I DQ = 500 μA, V DSQ = 6.25 V, R D = 7 kΩ, R S = 500 Ω V TN = 800 mV, K n = 1 mA/V 2 , λ = 0 V 1 Lecture 16 Page 2
Common-Source Amplifier with a Bypass Capacitor λ = 0 V −1 EE 310 Lecture 16 Lecture 16 Page 3

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Model of CS Amplifier with Bypass Capacitor

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Unformatted text preview: Solve for the Voltage Gain: K n = 1 mA/V 2 , V TN = 0.8 V, Î» = 0 V âˆ’1 EE 310 Lecture 16 Lecture 16 Page 4 The Common-Drain Amplifier (a.k.a. Source Follower) Sketch a model for this circuit: EE 310 Lecture 16 Lecture 16 Page 5 The CD Amplifier (Continued) Model rearranged: EE 310 Lecture 16 Lecture 16 Page 6...
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## This note was uploaded on 10/12/2010 for the course E E 310 at Pennsylvania State University, University Park.

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Lecture_16 - Solve for the Voltage Gain K n = 1 mA/V 2 V TN = 0.8 V Î = 0 V âˆ’1 EE 310 Lecture 16 Lecture 16 Page 4 The Common-Drain

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